4.22 grams.
1. First find out how much AgNO3 weighs with one mole (107.87 g Ag + 14.007 g N + 48 g O = 169.89 grams)
2. Find the percent of Ag you have. So, (107.87 g/mol Ag)/(169.89 g/mol AgNO3)= 0.63 * 100 = 63%.
3. If you have 6.7 grams total, you know 63% of it is going to be silver, so just multiply 6.7 grams by .63 and you get 4.22 g Ag
Answer:
The answer is
<h2>3.68 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
<h3>

</h3>
From the question
mass of substance = 12.50 g
volume = 3.4 mL
The density of the substance is

We have the final answer as
<h3>3.68 g/mL</h3>
Hope this helps you
Answer:
2.94 x
Explanation:
First we need to find out how many moles of ammonia there are, using the formula: Mass = mr x moles.
We know the mass is 83.1g, now we need to find the mR of ammonia - NH3.
N = 14, H = 1, so 14 + (3x1) = an mr of 17.
Moles = mass/ mr = 83.1/17 = 4.8882
Now we can multiply the moles by avogadro's constant to find the number of molecules:
4.8882 x (6.02 x
) = 2.94 x
molecules of ammonia
the Orange side will grow higher bc people on the blue side will eventually become over 65
Answer:
The sum of the coefficients in the balanced equation is 11
Explanation:
A reaction where an organic compound reacts with oxygen to produce carbon dioxide and water is called combustion.
The balance reaction of combustion for methanol is:
2CH₃OH (l) + 3O₂(g) → 2CO₂(g) + 4H₂O (g)
Coefficients from stoichiometry are 2, 3, 2 and 4
Sum = 2 + 3 + 2 + 4 = 11