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Nadya [2.5K]
3 years ago
12

Calculate the mass in grams of calcium carbonate present in a 50.00 mL sample of an aqueous calcium carbonate standard, assuming

the standard is known to have a hardness of 75.0 ppm (hardness due to CaCo3)
density of the sample is .9977 g/mL and the molar mass of calcium carbonate is 100.0 g/mol

show all work
Chemistry
1 answer:
Assoli18 [71]3 years ago
7 0
The units of ppm means parts per million. Also, It is equivalent to milligrams per liter. It is one way of expressing concentration of a substance. It u<span>sually used to describe the concentration of something in water or soil. We calculate the mass of CaCO3 as follows:

Mass = 75 mg/L (.050 L) = <span>3.75 mg CaCO3</span></span>
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what is the empirical formula of vanadium 1 oxide given that 20.38 grams of vandium combines with oxygen to form 23.58 grams of
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Answer:

The empirical formula is V₂O

Empirical formula of a compound is the formula that shows the simplest whole number ratio of the atoms of elements in a given compound. Empirical formula is normally calculated when the mass of each element in a compound is known or the percentage composition by mass of each element in a compound is known.

Step by Step Explanation:

Step 1: Percentage composition of each element

Percentage composition=(mass of an element/ mass of the compound)100%

Mass of Vanadium = 20.38 g

Mass of the compound = 23.58 g

% composition of Vanadium = (20.38 g/23.58 g) 100%

                                                 = 86.43 %

Mass of Oxygen = 23.58 g -20.38 g

                           = 3.2 g

% composition of oxygen = (3.2/g/23.58 g) 100%

                                          =  13.57%

Step 2: Find the number of atoms of each element in the compound

Number of atoms  = percentage composition/ atomic mass

Atomic mass of Vanadium = 50.94 g/mol

Number of atoms of V = 86.43 /50.94

                                  = 1.6967

Atomic mass of oxygen = 16 g/mol

Number of atoms of O = 13.57/16

                                      = 0.8481

Step 3:  Find the simplest ratio of atoms

Vanadium : Oxygen

            1.6967 : 0.8481

= 1.6967/0.8481 : 0.8481/0.8481

= 2: 1

Whole number ratio = 2 : 1

Therefore; the empirical formula is V₂O

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