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3 years ago

Please help No Explanation needed. Its science please

Chemistry

1 answer:

aksik [14]3 years ago

3 0

Answer:

C, A, A, B, B

Explanation:

Question 5: C. continental drift

Question 6: A. new rock forms

Question 7: A. happens at deep-ocean trenches

Question 8: B. convection currents in the mantle

Question 9: B. convergent boundary

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3 years ago

Need help on question 3 plz<br> URGENT HELP PLZ

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4 years ago

Given the following balanced equation, if the rate of O2 loss is 3.64 × 10-3 M/s, what is the rate of formation of SO3? 2 SO2(g)

Fynjy0 [20]

Answer:

Rate of formation of SO₃ $[\frac{d[SO_{3}] }{dt}]$ = 7.28 x 10⁻³ M/s

Explanation:

According to equation 2 SO₂(g) + O₂(g) → 2 SO₃(g)

Rate of disappearance of reactants = rate of appearance of products

⇒ $-\frac{1}{2} \frac{d[SO_{2} ]}{dt} = -\frac{d[O_{2} ]}{dt}=\frac{1}{2} \frac{d[SO_{3} ]}{dt}$ -----------------------------(1)

Given that the rate of disappearance of oxygen = $-\frac{d[O_{2} ]}{dt}$ = 3.64 x 10⁻³ M/s

So the rate of formation of SO₃ $[\frac{d[SO_{3}] }{dt}]$ = ?

from equation (1) we can write

$\frac{d[SO_{3}] }{dt} = 2 [-\frac{d[O_{2}] }{dt} ]$

⇒ $\frac{d[SO_{3}] }{dt}$ = 2 x 3.64 x 10⁻³ M/s

⇒ $[\frac{d[SO_{3}] }{dt}]$ = 7.28 x 10⁻³ M/s

∴ So the rate of formation of SO₃ $[\frac{d[SO_{3}] }{dt}]$ = 7.28 x 10⁻³ M/s

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4 years ago

A. What was the pH change when HCI was added to tap water?

Oxana [17]

Answer:

See below.

Explanation:

a. The pH would decrease.

b. An acid.

c. The pH would increase.

d. A base. More accurately an alkali ( which is a soluble base).

5 0

3 years ago

Read 2 more answers