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AysviL [449]
3 years ago
11

A 2.3 m -long wire carries a current of 8.6 A and is immersed within a uniform magnetic field B⃗ . When this wire lies along the

+x axis, a magnetic force F⃗ =(−2.0j)N acts on the wire, and when it lies on the +y axis, the force is F⃗ =(2.0i−4.8k)N.
Physics
1 answer:
Volgvan3 years ago
5 0

Answer:

Explanation:

Given that :

The current I = 8.6 A

The length vector L = 2.3 m i

The force vector is = -2.0 j N

When L = 2.3 m i ; the

Force vector F = (2.0 i - 4.8 k) N

Compute the components of the magnetic field as follows:

F = I(L*B)

Replacing 8.6 A for I ; -2.0 j N for F & 2.3 m i for L

-2.0 j N = (8.6 A) (2.3 m i *(B_xi + B_yj+B_zk)

-2.0 j N = 19.78B_z \ and  \ 0 = 19.78B_y

B_z = -0.1011 T  \ and \ B_y = 0

However in y direction ; we have :

(2.0 i - 4.8 k) = 8,6 A (2.3 mi*(B_xi+B_yj+B_zk)

- 2.0 = 19.78 B_z \ and \ -4.8 = 19.78 B_x

B_z = -0.1011 T \ and \ B_x = -0.2427T

Hence, the component of magnetic field is as follows:

B_x = -.02427T \ ; B_y = 0 T \  ; B_z =  - 0.1011 T)

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How many million Christmas trees were sold in the year 2000?
Sergio039 [100]

Explanation:

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5 0
3 years ago
4. Going back to the dog whistle in question 1, what is the minimum riding speed needed to be able to hear the whistle? Remember
jeyben [28]

Answer:

The minimum riding speed relative to the whistle (stationary) to be able to hear the sound at 21.0 kHz frequency is 15.7  m/s

Explanation:

The Doppler shift equation is given as follows;

f' = \dfrac{v - v_o}{v + v_s} \times f

Where:

f' = Required observed frequency = 20.0 kHz

f = Real frequency = 21.0 kHz

v = Sound wave velocity = 330 m/s

v_o = Observer velocity = X m/s

v_s = Source velocity = 0 m/s (Assuming the source is stationary)

Which gives;

20 = \dfrac{330- v_o}{330+0} \times 21

330 - v_o = (20/21)*330

v_o = 330 - (20/21)*330 = 15.7 m/s

The minimum riding speed relative to the whistle (stationary) to be able to hear the sound at 21.0 kHz frequency = 15.7  m/s.

8 0
3 years ago
A video store owner noticed a 5% drop in rentals of DVDs after raising her prices 10%. Are DVD rentals
lukranit [14]

Answer:

Inelastic

Explanation:

The price elasticity of demand is the degree of responsiveness of demand for a product or service to a unit change in price. The demand for a product is said to be elastic when a change in price has a relatively large effect on the demand for the product, unitary when there is a percentage change in price brings about an equal percentage change in the demand for the product, and inelastic when a change in the price of a product brings about a smaller change in the demand for the product.

<em>In the case of the DVD rentals, a 10% increase in price brought about only a 5% drop in demand. Hence, the demand for DVD rentals is said to be inelastic because a change in the price brought about a smaller change in the demand for DVD rentals.</em>

8 0
3 years ago
Several years from now you have graduated with an engineering/physics degree and have been hired by a nanoengineering firm as an
nadya68 [22]

Answer:

See attached handwritten document for answer

Explanation:

5 0
3 years ago
An object weighs 79.1 N in air. When it is suspended from a force scale and completely immersed in water the scale reads 21.8 N.
Free_Kalibri [48]

Answer:

(a). The density of the object is 1382 kg/m³.

(b). The density of the oil is 536.4 kg/m³.

Explanation:

Given that,

Weight in air = 79.1 N

Weight in water = 21.8 N

Weight in oil = 48.4 N

We need to calculate the volume of object

Using formula of buoyant force

F_{b}=W_{air}=W_{water}

F_{b}=79.1-21.8

F_{b}=57.3\ N

F_{b}=\rho g h

Put the value into the formula

57.3=1000\times V\times 9.8

V=\dfrac{57.3}{1000\times9.8}

V=5.84\times10^{-3}\ m^3

We need to calculate the density

Using formula of buoyant force

F_{b}=\rho Vg

79.1=\rho\times5.84\times10^{-3}\times9.8

\rho=\dfrac{79.1}{5.84\times10^{-3}\times9.8}

\rho=1382\ kg/m^3

The density of the object is 1382 kg/m³.

(b). We need to calculate the volume of object

Using formula of buoyant force

F_{b}=W_{air}=W_{oil}

F_{b}=79.1-48.4

F_{b}=30.7\ N

We need to calculate the density

Using formula of buoyant force

F_{b}=\rho_{oil} Vg

30.7=\rho_{oil}\times5.84\times10^{-3}\times9.8

\rho_{oil}=\dfrac{30.7}{5.84\times10^{-3}\times9.8}

\rho=536.4\ kg/m^3

The density of the oil is 536.4 kg/m³.

Hence, This is the required solution.

4 0
3 years ago
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