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tigry1 [53]
3 years ago
10

Which of the following would accurately label the X axis?

Physics
1 answer:
kogti [31]3 years ago
6 0

Answer: Distance

I’m not sure if it is correct, but I am pretty sure it is......

I hope this helps :)

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Displacement is the change in velocity of an object.<br><br> True or false
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Words less true are seldom if ever spoken.


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A 1250 kg car is pulling a 325 kb trailer. The car and trailer have an acceleration of 2,15m/sec2 together. Determine the net fo
xenn [34]

To solve this problem we will apply the definition of Newton's second law, which says that force is equivalent to body mass by acceleration. In this case the mass of the trailer is 325Kg and its acceleration is 2.15m / s ^ 2, so we will proceed to replace and multiply these values to find the net force on this object.

F= ma

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Under the reference system in which the direction of travel is the positive direction, the direction of the force will be positive.

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3 years ago
What are the laws of Physics​
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8 0
2 years ago
Find the object's speeds v1, v2, and v3 at times t1=2.0s, t2=4.0s, and t3=13s.
Burka [1]
Since this is a distance/time graph, the speed at any time is the slope
of the part of the graph that's directly over that time on the x-axis.

At time  t1 = 2.0 s
That's in the middle of the first segment of the graph,
that extends from zero to 3 seconds.
Its slope is  7/3 .              v1 = 7/3 m/s .

At time  t2 = 4.0 s
That's in the middle of the horizontal part of the graph
that runs from 3 to 6 seconds.
Its slope is zero.
                                     v2 = zero .

At time  t3 = 13 s.
That's in the middle of the part of the graph that's sloping down,
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2 years ago
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A weightlifter is attempting a biceps curl with a 200 n barbell. the moment arm of the barbell about the elbow joint is 40 cm. t
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Weight of the barbell W = 200 Ndistance of the joint is r = 40 cm = 0.4 mtorque created by the weight at the joint is                  τ = F*r                     = 200 N*0.4 m                     = 80 N.mat equilibrium condition ,    Στ = force*distance - 80 N.m = 0             F'*0.4 - 80 N.m = 0             F'*0.4 = 80          force F' = 200 N
4 0
3 years ago
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