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Zinaida [17]
4 years ago
5

Distinguish between resultant and equilibrant forces​

Physics
1 answer:
SIZIF [17.4K]4 years ago
4 0

Answer:

resultant is a single force that can replace the of a number of forces , equililbrant is a force that is exactly opposite to resultant

Explanation:

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A box slides down a ramp inclined at 24◦ to the horizontal with an acceleration of 1.7 m/s 2 . The acceleration of gravity is 9.
dsp73

Answer:

<h3>0.445</h3>

Explanation:

In friction, the coefficient of friction formula is expressed as;

\mu = \frac{F_f}{R}

Ff is the frictional force = Wsinθ

R is the reaction = Wcosθ

Substitute inti the equation;

\mu = \frac{Wsin \theta}{W cos\theta} \\\mu = \frac{sin \theta}{cos\theta} \\\mu = tan \theta

Given

θ = 24°

\mu = tan 24^0\\\mu = 0.445\\

Hence the coefficient of kinetic friction between the box and the ramp is 0.445

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3 years ago
Please help, i only need help with 2,5, and 7
svet-max [94.6K]

Answer:

2. Galaxy

5. Electromagnetic radiation

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6 0
3 years ago
A runner is jogging in a straight line at a
murzikaleks [220]

Explanation:

The runner was 8.6km away from the finish line when the bird starts flying.

Therefore it takes the bird 8.6/14.4 = 0.60 hours for the bird to fly to the finish line.

In that 0.60 hours, the runner would have ran an extra 3.6km/h * 0.6h = 2.16km.

Now, the runner and the bird are flying towards each other. The distance between them is 8.6 - 2.16 = 6.44km and their combined speed is 18.0km.

Hence, they will meet in 6.44/18.0 = 0.36 hours.

Overall, the bird flew for 0.60 + 0.36 = 0.96 hours, and flew 14.4km/h * 0.96h = 13.8km.

4 0
3 years ago
A passenger travels from the first floor to the 60th floor, a distance of 210 m in 35 s. what is the elevators speed
Sati [7]
  • Distance=210m
  • Time=35s

\\ \tt\bull\leadsto Speed=\dfrac{Distance}{Time}

\\ \tt\bull\leadsto Speed=210/35=6m/s

3 0
3 years ago
Read 2 more answers
A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a very light rope that goes over an ideal pulley. If the
AleksAgata [21]

Answer:

acceleration = 2.4525‬ m/s²

Explanation:

Data: Let m1 = 3.0 Kg, m2 = 5.0 Kg, g = 9.81 m/s²

Tension in the rope = T

Sol: m2 > m1

i) for downward motion of m2:

m2 a = m2 g - T

5 a = 5 × 9.81 m/s² - T  

⇒ T = 49.05‬ m/s² - 5 a     Eqn (a)‬

ii) for upward motion of m1

m a = T - m1 g

3 a = T - 3 × 9.8 m/s²

⇒ T =  3 a + 29.43‬ m/s²   Eqn (b)

Equating Eqn (a) and(b)

49.05‬ m/s² - 5 a = T =  3 a + 29.43‬ m/s²

49.05‬ m/s² - 29.43‬ m/s² = 3 a + 5 a

19.62 m/s² = 8 a

⇒ a = 2.4525‬ m/s²

5 0
3 years ago
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