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brilliants [131]
2 years ago
14

Identify the conjugate base in each pairs

Chemistry
1 answer:
DiKsa [7]2 years ago
8 0

Answer: 1) RCOO^-

2) H_2PO_4^-

3) RNH_2

4) HCO_3^-

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

1) RCOOH\rightarrow RCOO^-+H^+

Here, RCOOH is loosing a proton, thus it is considered as an acid and after losing a proton, it forms RCOO^- which is a conjugate base.

2) H_3PO_4\rightarrow H_2PO_4^-+H^+

Here, H_3PO_4 is loosing a proton, thus it is considered as an acid and after losing a proton, it forms H_2PO_4^- which is a conjugate base.

3) RNH_3^+\rightarrow RNH_2+H^+

Here, RNH_3^+ is loosing a proton, thus it is considered as an acid and after losing a proton, it forms RNH_2 which is a conjugate base.

4) H_2CO_3\rightarrow HCO_3^-+H^+

Here, H_2CO_3 is loosing a proton, thus it is considered as an acid and after losing a proton, it forms HCO_3^- which is a conjugate base.

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c_{p,l} = specific heat of liquid benzene = 1.73J/g^oC=1.73J/g.K

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Q=[94.4g\times 1.73J/g.K\times (279-322)K]+[94.4g\times -125.6J/g]+[94.4g\times 1.51J/g.K\times (205-279)K]

Q=-29427.312J=-29.4kJ

Negative sign indicates that the heat is removed from the system.

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