Answer:
joules
joules
Explanation:
Let us convert the time in hours into seconds
Change in internal energy
where E is the internal energy in Joules
p is the power in watts
and t is the time in seconds
Joules
Amount of work done by the system
where P is the pressure and V is the volume
Substituting the given values in above equation, we get -
liter-atmospheres
Work done in Joules
Joules
Substituting the given values we get -
Thus
joules
joules
Check this Light doesn't have mass or gravity right?
So if it doesn't have mass or gravity so light can only affect objects with mass
Does that make sense?
The black hole has gravity and remember light doesn't have gravity so does it affect the light?
To answer that yes, and since light doesn't have gravity it gets "pulled" into the black hole
I hope this helps you
Answer: Frequency factor A = 8 × 10⁹
activation energy Ea = 15.5 KJ/Mol
Explanation: to begin, let us first define the parameters given;
K₁ = 1.44 × 10⁷dm³mol⁻¹s⁻¹
K₂ = 3.03 × 10⁷ dm³mol⁻¹s⁻¹
K₃ = 6.9 × 10 dm³mol⁻¹s⁻¹
also T₁ = 300.3 K
T₂ = 341.2 K
T₃ = 392.2 K
we know that;
㏑ K₂ / K₁ = Ea/R [1/T₁ -1/T₂]
where R is given as 8.314 J/mol-k
Ea = activation energy
K₁, K₂ = rate constant
T₁, T₂ = Temperature
therefore, ㏑ (3.03 × 10⁷/ 1.44 × 10⁷) = Ea / 8.314 [1/300.3 - 1/341.2]
this gives Ea = 15496.16 J/Mol ≈ 15.5 KJ /Mol
∴ Ea = 15.5 KJ/ Mol
also given that K = A e⁻∧Ea/RT
here A = frequency factor
∴ 6.9 × 10⁷ = A e⁻ ∧(15496.16/8.314 × 392.2)
A = 7.99 × 10⁹ = 8 × 10⁹
Answer:
Alice Distance = 100 meters
Peter's Distance = 3 km
Alice Displacement and Peter's displacement are both 100 meters upwards.
Explanation:
To solve this question, we have to first define distance and displacement.
Distance is simply the measurement of the sum of all paths travelled from one point to another while displacement is measurement of the shortest distance from initial point to final point.
Now, Alice and Peter are moving from the same point.
Alice distance travelled is 100 meters.
Also, her displacement will be 100 meters because it is the shortest distance to the summit of the cliff.
Now, for Peter, he decides to take a longer route which is 3 km in distance.
However, the shortest path which is the displacement is still 100 meters.
Thus, Peter's displacement is 100 meters.
