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Alexus [3.1K]
3 years ago
15

A transformer consists of a 500 turn primary coil and a 2000-turnsecondary coil. If the current in the secondary is 3.0A, what i

sthe current in the primary?and WHy?
Physics
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer:

The correct solution will be "12.0 A".

Explanation:

The given values are:

N_p= 500 \ turn

N_s= 200 \ turn

I_s= 3.0 \ A

By using the transformer formula, we get

⇒ \frac{N_p}{N_s}  =\frac{I_s}{I_p}

⇒ I_p = I_s\times \frac{N_s}{N_p}

On substituting the given values, we get

⇒      =3.0 \ A\times \frac{2000}{500}

⇒      =12.0 \ A

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When there is a change in magnetic flux linkage through a loop of wire, an electromotive force is induced in the loop, according to the Faraday-Newmann-Lenz Law:

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The negative sign in the formula represents Lenz's Law, and tells us about the direction of the electromotive force.

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The negative sign in Lenz's Law tells exactly this: the direction of the induced emf is such that it opposes the initial change in magnetic flux that generated the induced emf, so that overall the total energy is conserved.

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