Answer:
The values is 
Explanation:
From the question we are told that
The slit distance is 
The wavelength is 
At the first half of the screen from the central maxima
The number of bright spot according to the condition for constructive interference is

For maximum number of spot 
So


Now for the both sides plus the central maxima we have

substituting values


Answer:
<em>The object could fall from six times the original height and still be safe</em>
Explanation:
<u>Free Falling</u>
When an object is released from rest in free air (no friction), the motion is completely dependant on the acceleration of gravity g.
If we drop an object of mass m near the Earth surface from a height h, it has initial mechanical energy of

When the object strikes the ground, all the mechanical energy (only potential energy) becomes into kinetic energy

Where v is the speed just before hitting the ground
If we know the speed v is safe for the integrity of the object, then we can know the height it was dropped from

Solving for h

If the drop had occurred in the Moon, then

Where hM, vM and gM are the corresponding parameters on the Moon. We know v is the safe hitting speed and the gravitational acceleration on the Moon is g_M=1/6 g


This means the object could fall from six times the original height and still be safe
Answer:
The cart will accelerate to the left
Explanation:
The cart is initially at rest. In order to understand its motion, we should consider the net force acting on the cart. We have two forces acting on it:
- A force of 7 N to the left
- A force of 5 N to the right
Therefore, the net force is

in the direction of the stronger force (so, to the left).
According to Newton's second law:

a net force different from zero produces an acceleration of the object, in the same direction as the net force. Therefore, the cart will accelerate to the left.
It’s due to the refraction of light rays as they traverse the boundary between water and air. The greater the viewing angle, the more the bending of the light and therefore the less the apparent depth. An object placed in a denser medium, when viewed from rarer medium appears to be at a lesser depth than its real depth due to refraction of light.
The solution for the problem is:
1 Watt = 1 Joule per second
1 Watt*second = 1 Joule
a Kilowatt is 1,000 Watts
an hour is 60 seconds times 60 minutes or 3,600 seconds
a Kilowatt * hour is 1,000 Watts in 3,600 seconds
15 W*h = 15,000 Watt*hour = 15,000 Watt * 3,600 seconds = 54,000,000
Watt*second
54,000,000 Watt*second = ? Joules
54,000,000 Joules / second = 54,000,000 Watts