It requires 2,500 joules to raise a certain amount of water (c = 4.186J/g°C) from 20.0°C to 65.0°C.
1 answer:
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We need to use the following formula
Δ
n= 4 moles
F= constant= 96500C/mol
let's plug in the values.
ΔG= -(4)(96500)(0.24)= -92640 J or -92.6 kJ
Δ
n= 4 moles
F= constant= 96500C/mol
let's plug in the values.
ΔG= -(4)(96500)(0.24)= -92640 J or -92.6 kJ