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kirza4 [7]
3 years ago
15

Se lanza una pelota de hule elástica de masa mA con una velocidad VAi contra la puerta trasera de un camión muy pesado de masa m

B que se encuentra en reposo ¿Cuáles son las velocidades de ambos objetos después de la colisión? Suponga un choque elástico.
Physics
1 answer:
miv72 [106K]3 years ago
3 0

Answer:

v_{A}=v_{Ai}

Explanation:

The total momentum of the system must conserve by the law of momentum conservation.

p_b=p_a\\\\m_Av_{Ai}+m_Bv_{Bi}=m_Av_{A}+m_Bv_{B}    ( 1 )

If you consider the shock between the ball and the truck as totally elastic, and also if the truck is much more massive than the ball, you can assume that the truck does not move when the ball hits it.

Then the truck is always at rest

Hence, you have in the expression ( 1 ):

m_Av_{Ai}+0=m_Av_{A}+0\\\\v_{Ai}=v_{A}

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A 0.4000 kg sample of methanol at 16.0ºC is mixed with 0.4000 kg of water at 85.0ºC. Assuming no heat loss to the surroundings,
AVprozaik [17]

Answer:

T_finalmix = 59.5 [°C].

Explanation:

In order to solve this problem, a thermal balance must be performed, where the heat is transferred from water to methanol, at the end the temperature of the water and methanol must be equal once the thermal balance is achieved.

Q_{water}=Q_{methanol}

where:

Q_{water}=m_{water}*Cp_{water}*(T_{waterinitial}-T_{final})

mwater = mass of the water = 0.4 [kg]

Cp_water = specific heat of the water = 4180 [J/kg*°C]

T_waterinitial = initial temperature of the water = 85 [°C]

T_finalmix = final temperature of the mix [°C]

Q_{methanol}=m_{methanol}*Cp_{methanol}*(T_{final}-T_{initialmethanol})

Now replacing:

0.4*4180*(85-T_{final})=0.4*2450*(T_{final}-16)\\142120-1672*T_{final}=980*T_{final}-15680\\157800=2652*T_{final}\\T_{final}=59.5[C]

4 0
3 years ago
Which of the following is NOT a property of long-period comets that suggests that they originate from the Oort cloud?
Lesechka [4]

Answer:

b. They orbit around the Sun in a counterclockwise direction, when viewed from above the ecliptic plane.

Explanation:

All the objects of the solar system revolve around the Sun in a counterclockwise direction. The comet coming from the Oort's cloud will also follow the same kind of orbit. That is why it can't be a property to distinguish an Oort's cloud comet.

All other properties are correct to identify an Oort's cloud comet as the Oort's cloud is a considered a spherical cloud just outside the Solar system.

7 0
3 years ago
1) Si un mango cae a una velocidad de 75m/s y tarda 26 seg. en caer. ¿ Cuál habrá sido la velocidad con qué el mango llegó al su
Lyrx [107]

Answer:

El mango llega al suelo a una velocidad de 329.982 metros por segundo.

Explanation:

El mango experimenta un movimiento de caída libre, es decir, un movimiento uniformemente acelerado debido a la gravedad terrestre, despreciando los efectos de la viscosidad del aire y la rotación planetaria. Entonces, la velocidad final del mango, es decir, la velocidad con la que llega al suelo, se puede determinar mediante la siguiente fórmula cinemática:

v = v_{o}+g\cdot t (1)

Donde:

v_{o} - Velocidad inicial, en metros por segundo.

v - Velocidad final, en metros por segundo.

g - Aceleración gravitacional, en metros por segundo al cuadrado.

t - Tiempo, en segundos.

Si sabemos que v_{o} = -75\,\frac{m}{s}, g = -9.807\,\frac{m}{s^{2}} y t = 26\,s, entonces la velocidad final del mango es:

v = v_{o}+g\cdot t

v = -75\,\frac{m}{s}+\left(-9.807\,\frac{m}{s} \right)\cdot (26\,s)

v = -329.982\,\frac{m}{s}

El mango llega al suelo a una velocidad de 329.982 metros por segundo.

8 0
3 years ago
In ionic compounds which group from the periodic table usually provide anion?
koban [17]
Pretty sure it’s halogens , or groups 14-17
3 0
3 years ago
Which force is responsible for contact forces
Liula [17]
Electromagnetic force
6 0
3 years ago
Read 2 more answers
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