A match-head is flammable, but you have to get it up to its ignition temperature first.
A diamond is flammable, but its ignition temperature is astronomical and
totally out of sight.
Answer:
There are
1.479
×
10
−
13
concentration of hydrogen ions
m
o
l
L
.
Explanation:
Because pH is a logarthmic scale, we can use the formula:
[
H
+
]
=
10
-pH
. Where...
=>
[
H
+
]
is the concentration of hydrogen ions in the solution.
=>
p
H
is the pH of the solution.
=> Where
10
is the base of the power - it's a logarithm formula.
We can now just sub in the values and solve for [
H
+
]
.
[
H
+
]
=
10
-pH
=
10
−
(
12.83
)
=
1.479108388
×
10
−
13
We can round (if required) to
1.479
×
10
−
13
.
Thus, there are
1.479
×
10
−
13
concentration of hydrogen ions
m
o
l
L
.
Hope this helps :)
Answer:
D.141 g
Explanation:
Given that:-
Mass of ethylene = 45.0 g
Molar mass of ethylene = 28.05 g/mol
The formula for the calculation of moles is shown below:
Thus,
According to the reaction below:-
1 mole of ethylene produces 2 moles of carbon dioxide
So,
1.60 mole of ethylene produces 2*1.60 moles of carbon dioxide
Moles of carbon dioxide = 3.2 mol
Molar mass of carbon dioxide = 44.01 g/mol
Mass = Moles*Molar mass = 3.2 mol x 44.01 g/mol = 141 g
<u>D.141 g of carbon dioxide will be produced</u>
Answer:
See explanation.
Explanation:
Hello there!
In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:
Thus, we proceed as follows:
Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:
Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:
Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:
Best regards!
Answer:
No. of molecules= mass/molar mass ×avogadro no.
= 13.2/50×6.02×10°23
No. of molecules =1.59×10°23
Explanation: