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natima [27]
3 years ago
13

Twenty students were surveyed to find out how many hours of TV they watch during a school week. The results are shown to the rig

ht. Answer the following questions and round your answers to the nearest half hour. The mean of the data is ____ hours.
Chemistry
2 answers:
natulia [17]3 years ago
8 0

Answer: 4.5

Explanation:

Just did it

alexandr402 [8]3 years ago
3 0

Answer:

5 Hours

Explanation: I just wanted to save your time and i added all the hours up divided by 20 which i got 4.95 then rounded up to 5.

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How do you convert ethane to ethanoic acid? (with equation please).
Bess [88]
Ethane can be turned into its carboxylic acid form called the ethanoic acid by a series of steps. First chlirinate it in the presence of light. Then, add potassium hydroxide to get an alcohol. Finally, adding KMnO4 to oxidize it to a carboxylic acid. The equations are as follows:
C2H6 + Cl2  ---> C2H5Cl + HCl
C2H5Cl+KOH-> C2H5OH+ KCl.
C2H5OH  ----KMnO4 ---> CH3COOH.
4 0
3 years ago
Read 2 more answers
Select the correct layer.<br> In which layer is lithification most likely to occur?
Vera_Pavlovna [14]

Answer:

"Subsoil" is the correct answer.

Explanation:

  • The method of transforming sediments become rocky solids is considered as Lithification. The floor stratum or level below the upper floors at the base of the floor is a Subsoil.
  • Sediments comprise materials particles like sand, pebbles, skeletons kind of bones as well as muck, that were transported and produced instead in water or perhaps wind someplace.
8 0
3 years ago
The equilibrium constant Kp for the reaction (CH3),CCI (g) = (CH3),C=CH, (g) + HCl (g) is 3.45 at 500. K. (5.00 x 10K) Calculate
Karolina [17]

<u>Answer:</u> The value of K_p for the reaction is 6.32 and concentrations of (CH_3)_2C=CH,HCl\text{ and }(CH_3)_3CCl is 0.094 M, 0.094 M and 0.106 M respectively.

<u>Explanation:</u>

Relation of K_p with K_c is given by the formula:

K_p=K_c(RT)^{\Delta ng}

where,

K_p = equilibrium constant in terms of partial pressure = 3.45

K_c = equilibrium constant in terms of concentration = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature = 500 K

\Delta n_g = change in number of moles of gas particles = n_{products}-n_{reactants}=2-1=1

Putting values in above equation, we get:

3.45=K_c\times (0.0821\times 500)^{1}\\\\K_c=\frac{3.45}{0.0821\times 500}=0.084

The equation used to calculate concentration of a solution is:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume (in L)}}

Initial moles of (CH_3)_3CCl(g) = 1.00 mol

Volume of the flask = 5.00 L

So, \text{Concentration of }(CH_3)_3CCl=\frac{1.00mol}{5.00L}=0.2M

For the given chemical reaction:

                (CH_3)_3CCl(g)\rightarrow (CH_3)_2C=CH(g)+HCl(g)

Initial:               0.2                    -                        -

At Eqllm:          0.2 - x               x                       x

The expression of K_c for above reaction follows:

K_c=\frac{[(CH_3)_2C=CH]\times [HCl]}{[(CH_3)_3CCl]}

Putting values in above equation, we get:

0.084=\frac{x\times x}{0.2-x}\\\\x^2+0.084x-0.0168=0\\\\x=0.094,-0.178

Negative value of 'x' is neglected because initial concentration cannot be more than the given concentration

Calculating the concentration of reactants and products:

[(CH_3)_2C=CH]=x=0.094M

[HCl]=x=0.094M

[(CH_3)_3CCl]=(0.2-x)=(0.2-0.094)=0.106M

Hence, the value of K_p for the reaction is 6.32 and concentrations of (CH_3)_2C=CH,HCl\text{ and }(CH_3)_3CCl is 0.094 M, 0.094 M and 0.106 M respectively.

8 0
3 years ago
How many molecules of CF₂Cl₂ are in 45.7 grams of CF₂Cl₂? (Show work)
posledela

Answer:

The answer to your question is: 2.20 x 10 ²³ molecules

Explanation:

Data

mass = 45.7 g

molecules of CF₂Cl₂ = ?

Process

1.- Calculate the mass number of CF₂Cl₂

   C = 12    F =2 x 19    Cl = 2 x 35.5

   total = 12 + 38 + 71

   total = 121 g

2.- Use the Avogradro's number to solve the problem

                       121 g -------------------  6.023 x 10²³ molecules of CF₂Cl₂

                        45.7 g ---------------     x

                        x = (45.7 x 6.023 x 10²³) / 121

                        x = 2.75 x 10²⁵ / 121

                        x = 2.20 x 10 ²³ molecules

4 0
3 years ago
What are the answers to the blanks to make this equation balanced
Eddi Din [679]

1Al+6NaOH==>2Na_{3}AlO_{3}+3H_{2}


Hope this helps!

5 0
3 years ago
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