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Answer: 2175.68 J heat is required to increase the temperature of 20 grams of water by 26 degrees celsius.
Explanation:
Given: Mass = 20 g
Change in temperature =
The standard value of specific heat of water is
Formula used to calculate the heat energy is as follows.
where,
q = heat energy
m = mass of substance
C = specific heat of substance
= change in temperature
Substitute the values into above formula as follows.
Thus, we can conclude that 2175.68 J heat is required to increase the temperature of 20 grams of water by 26 degrees celsius.