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Mars2501 [29]
3 years ago
7

As a roller coaster car crosses the top of a 50-m-diameter loop-the-loop, its apparent weight is the same as its true weight.

Physics
1 answer:
scZoUnD [109]3 years ago
3 0

Answer:22.36 m/s

Explanation:

Given

the diameter of loop d=50 m

the radius of loop r=25 m

At the top position, we can write,

weight and Normal reaction combination will provide the centripetal force i.e.

R+W=\frac{mv^2}{r}

R=W\quad \quad [\text{apparent weight =Actual weight}]

2W=2mg=\frac{mv^2}{r}

v=\sqrt{2gr}

v=\sqrt{2\times 10\times 25}

v=22.36\ m/s

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Answer:

Option D. is the correct choice.

Explanation:

Resistances connected in series add up to give equivalent resistance.

R_eq = 10+20+30 = 60 ohm

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A 1.70-μF capacitor is charging through a 14.0-Ω resistor using a 10.0- V battery. What will be current when the capacitor has a
RoseWind [281]

Answer:

The current is 0.951 A

Solution:

As per the question:

Capacitance of the capacitor, C = 1.70\mu F

Resistance of the circuit, R = 14.0\Omega

Voltage of the battery, V = 10.0 V

Now, when the charge become one-fourth of its initial value, the amount of current flowing is given by:

q' = q(1 - e^{-\frac{t}{\tau}})          (1)

where

q' = \frac{q}{4}

\tau = RC

q' = q(1 - e^{-\frac{t}{RC}})

\frac{q}{4} = q(1 - e^{-\frac{t}{RC}})

0.25 = (1 - e^{-\frac{t}{RC}})

0.75 = e^{-\frac{t}{RC}

-\frac{t}{RC} = ln(0.75)

-\frac{t}{14\times 1.70\times 10^{- 6}} = - 0.2876

t = 6.844\times 10^{- 6} s

Now,

The current is given by:

I' = Ie^{-\frac{t}{RC}}                  (2)

Also, I = \frac{V}{R} = \frac{10}{14} = 0.714 A

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3 years ago
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dalvyx [7]

Answer:

The gauge pressure as calculated is 5862.36 Pa

Solution:

As per the question:

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Av = A'v'                       (1)

where

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Since, the question assumes the stomach, mouth and esophagus as continuous vertical tube, then:

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P' - P = 997\times 9.8\times 0.6 = 5862.36\ Pa

5 0
4 years ago
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