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3 years ago

The girl is using her arm to lift a weight. Her arm is acting as a _______.

1 answer:

3 0

A pulley a wheel with a grooved rim around which a cord passes, which acts to change the direction of a force applied to the cord and is used to raise heavy weights.

So, the answer is a Pulley.

I hope this helps!

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Which statements describe the energy in a food web? Select three options.

hichkok12 [17]

Answer:

it loses engry it follows difernt paths

Explanation:

8 0

3 years ago

Ball 1, with a mass of 100 g and traveling at 10 m/s, collides head-on with ball 2, which has a mass of 300 g and is initially a

qaws [65]

There is 4000 balls in the earth of the world why is that so hard for you

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2 years ago

A cyclist rides 6.2 km east, then 9.28 km in a direction 27.27 degrees west of north, then 7.99 km west. A. What is the magnitud

Pani-rosa [81]

Answer:

Explanation:

given,

cyclist ride 6.2 km east and then 9.28 km in the direction of 27.27° west of north and then 7.99 km west.

vertical component = 9.28 cos∅

= 9.28 cos 27.27°

= 8.24 km

horizontal axis component = 9.28 sin ∅

= 9.28 sin 27.27°

= 4.5 km

distance of the final point from the origin

= 7.99 -(6.2-4.5)

= 6.29 km

displacement

$d = \sqrt{6.29^2+8.24^2}$

d = 10.37 km

b) $tan \theta = \dfrac{6.29}{8.24}$

θ = 37.36°

4 0

3 years ago

Una patinadora de 50 kg parte del reposo y después de recorrer 3k alcanza una velocidad de 15 m/s. ¿Qué fuerza neta experimenta

e-lub [12.9K]

Answer:

$F_{net} = 1.875\,N$

Explanation:

Asúmase que la patinadora experimenta una aceleración constante. La fuerza neta experimentada por la patinadora:

$F_{net} = (50\,kg)\cdot \left[\frac{\left(15\,\frac{m}{s}\right)^{2}-\left(0\,\frac{m}{s}\right)^{2} }{2\cdot (3000\,m)} \right]$

$F_{net} = 1.875\,N$

6 0

3 years ago

The first law of thermodynamics relates the heat transfer into or out of a system to the change of internal and the work done on

Artyom0805 [142]

Answer:

The heat transferred into the system is 183.5 J.

Explanation:

The first law of thermodynamics relates the heat transfer into or out of a system to the change of internal and the work done on the system, through the following equations.

ΔU = Q - W

where;

ΔU is the change in internal energy

Q is the heat transfer into the system

W is the work done by the system

Given;

ΔU = 155 J

W = 28.5 J

Q = ?

155 = Q - 28.5

Q = 155 + 28.5

Q = 183.5 J

Therefore, the heat transferred into the system is 183.5 J.

4 0

3 years ago