The human body station 2

What force is used to make the back-and-forth motion of a swing higher?

Eddi Din [679]

Answer:

its a

Explanation:

scrape - push or pull a hard or sharp implement across (a surface or object) so as to remove dirt or other matter.

5 0

2 years ago

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Based on the following equation, answer the questions below. ρ = (2γϕ + ψ)/rg where ρ [=] moles per cubic foot [mol/ft3] γ [=] j

AlekseyPX

1) Fundamental units of $\Psi$ are $[\frac{mol}{m\cdot s^2}]$

2) Fundamental units of $\Phi$ are $[\frac{mol}{m^3}]$

Explanation:

The equation for the variable $\rho$ is

$\rho =\frac{2\gamma \Phi+\Psi}{rg}$

where we have:

$\rho$ measured in $[\frac{mol}{ft^3}]$

$\gamma$ measured in $[\frac{J}{kg}]$

$r$ measured in $[in]$

$g$ measured in $[\frac{m}{s^2}]$

We can re-write the equation as

$\rho rg = 2\gamma \Phi + \Psi$

And we notice that the units of the term on the left must be equal to the units of the term on the right.

This means that:

1) First of all, $\Psi$ must have the same units of $\rho r g$ . So,

$[\rho r g]=[\frac{mol}{ft^3}][in][\frac{m}{s^2}]$

However, both ft (feet) and in (inches) are not fundamental dimensions: this means that they can be expressed as meters. Therefore, the fundamental units of $\Psi$ are

$[\Psi]=[\frac{mol}{m^3}][m][\frac{m}{s^2}]=[\frac{mol}{m\cdot s^2}]$

2)

The term $2\gamma \Phi$ must have the same units of $\Psi$ in order to be added to it. Therefore,

$[\gamma \Phi] = [\frac{mol}{m\cdot s^2}]$

We also know that the units of $\gamma$ are $[\frac{J}{kg}]$ , therefore

$[\frac{J}{kg}][\Phi]= [\frac{mol}{m\cdot s^2}]$

And so, the fundamental units of $\Phi$ are

$[\Phi]= [\frac{mol\cdot kg}{J\cdot m\cdot s^2}]$

However, the Joules can be written as

$[J]=[kg][\frac{m^2}{s^2}]$

Therefore

$[\Phi]= [\frac{mol\cdot kg}{(kg \frac{m^2}{s^2})\cdot m\cdot s^2}]=[\Phi]= [\frac{mol}{m^3}]$

#LearnwithBrainly

7 0

3 years ago

A horizontal spring is lying on a frictionless surface. One end of the spring is attached to a wall, and the other end is connec

juin [17]

Answer:

Explanation:

Given that:

angular frequency = 11.3 rad/s

Spring constant (k) = $= \omega^2 \times m$

k = (11.3)² m

k = 127.7 m

where;

$x_1$ = 0.065 m

$x_2$ = 0.048 m

According to the conservation of energies;

$E_1=E_2$

∴

$\Big(\dfrac{1}{2} \Big) kx_1^2 =\Big(\dfrac{1}{2} \Big) mv_2^2 + \Big(\dfrac{1}{2} \Big) kx_2^2$

$kx_1^2 = mv_2^2 + kx_2^2$

$(127.7 \ m) \times 0.065^2 = v_2^2 + (127.7 \ m) \times 0.048^2$

$0.5395325 = v_2^2 +0.2942208 \\ \\ 0.5395325 - 0.2942208 = v_2^2 \\ \\ v_2^2 = 0.2453117 \\ \\ v_2 = \sqrt{0.2453117} \\ \\ \mathbf{ v_2 \simeq0.50 \ m/s}$

4 0

3 years ago

If you see fire or smoke coming from your vehicle's hood, you should pull over and get away from the vehicle as soon as possible

hammer [34]

The given statement "If you see fire or smoke coming from your vehicle's hood, you should pull over and get away from the vehicle as soon as possible." is True.

What to do when there is smoking engine in your car?

You should take rapid action if the smoke seems to be coming from a fire under your bonnet.

shut off your vehicle

Don't try to prop the bonnet open; instead, pull the bonnet release lever.

Remove everyone from the vehicle and maintain your distance.

Ask for the fire service by dialing 999.

If it is safe to do so, warn oncoming traffic.

Learn more about the safety precaution with the help of the given link:

brainly.com/question/2347255

#SPJ4

8 0

1 year ago

Please explain how to solve this!! What is the power dissipated by a toaster that has a resistance of 60 ohms and is plugged int

babymother [125]

The power dissipated is simply V^2/R

where V = 120 volts RMS
and R = 60 Ω

5 0

3 years ago

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