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mihalych1998 [28]
4 years ago
13

Tech A says that the brake pedal uses leverage to multiply foot pressure. Tech B says that when braking hard while moving

Engineering
1 answer:
Nikolay [14]4 years ago
7 0

Tech- A is correct

Explanation:

  • Leverage is defined as using a tool to gain mechanical influence. The measure of the benefit gained depends on what kind of lever is used and how it is utilized.
  • Leverage is designed in such a way that it can reproduce the force from your leg many times before any force is transferred to brake fluid.
  • The brake pedal size and the measure of leverage received depends on the overall design of the brake system.
  • The second-order lever is used in the brake pedal. The brake pedal applies leverage to populate the force employed to the master cylinder. The effort needed to drive a load depends on the corresponding distance of the load and the work from the fulcrum. The proportion of load and work is known as mechanical advantage.
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If you think a hazard is serious, what is the best way to ensure that OSHA will
Umnica [9.8K]

Answer:

The best way to ensure that OSHA will conduct a site inspection is by the submission a signed (by a current employee or employee representative) Formal Written complaints following OSHA guidelines (which can be found in the  Council of Safety and Health (COSH) website) which will enable the commencement of process for an on site inspection

As such it is advisable to go through the following procedure before, filing a complaint

1) Talk to your workers union about the hazard

2) If you do not belong to a union, talk to your co-workers

3) Inform your employer who has responsibility for on the job safety

4) Speak or have a meeting with OSHA so as to receive guidance before filing a complaint

Explanation:

3 0
3 years ago
The shaft is made of A992 steel. It has a diameter of 1 in. and is supported by bearings at A and D, which allows free rotation.
zysi [14]

Answer:

the angle of twist of B with respect to D is -1.15°

the angle of twist of C with respect to D is 1.15°

Explanation:

The missing diagram that is supposed to be added to this image is attached in the file below.

From the given information:

The shaft is made of A992 steel. It has a diameter of 1 in and is supported by bearing at A and D.

For the Modulus of Rigidity  G = 11 × 10³ Ksi =  11 × 10⁶ lb/in²

The objective are :

1) To determine the angle of twist of B with respect to D

Considering the Polar moment of Inertia at the shaft J\tau

shaft J\tau = \dfrac{\pi}{2}r^4

where ;

r = 1 in /2

r = 0.5 in

shaft J \tau = \dfrac{\pi}{2} \times 0.5^4

shaft J\tau = 0.098218

Now; the angle of twist at  B with respect to D  is calculated by using the expression

\phi_{B/D} = \sum \dfrac{TL}{JG}

\phi_{B/D} = \dfrac{T_{CD}L_{CD}}{JG}+\dfrac{T_{BC}L_{BC}}{JG}

where;

T_{CD} \ \  and \ \  L_{CD} are the torques at segments CD and length at segments CD

{T_{BC} \  \ and  \ \ L_{BC}} are the torques at segments BC and length at segments BC

Also ; from the diagram; the following values where obtained:

L_{BC}} = 2.5  in

J\tau = 0.098218

G =  11 × 10⁶ lb/in²

T_{BC = -60 lb.ft

T_{CD = 0 lb.ft

L_{CD = 5.5 in

\phi_{B/D} = 0+ \dfrac{[(-60 \times 12 )] (2.5 \times  12 )}{ (0.9818)(11 \times 10^6)}

\phi_{B/D} = \dfrac{[(-720 )] (30 )}{1079980}

\phi_{B/D} = \dfrac{-21600}{1079980}

\phi_{B/D} = − 0.02 rad

To degree; we have

\phi_{B/D}  = -0.02 \times \dfrac{180}{\pi}

\mathbf{\phi_{B/D}  = -1.15^0}

Since we have a negative sign; that typically illustrates that the angle of twist is in an anti- clockwise direction

Thus; the angle of twist of B with respect to D is 1.15°

(2) Determine the angle of twist of C with respect to D.Answer unit: degree or radians, two decimal places

For  the angle of twist of C with respect to D; we have:

\phi_{C/D} = \dfrac{T_{CD}L_{CD}}{JG}+\dfrac{T_{BC}L_{BC}}{JG}

\phi_{C/D} = 0+\dfrac{T_{BC}L_{BC}}{JG}

\phi_{B/D} = 0+ \dfrac{[(60 \times 12 )] (2.5 \times  12 )}{ (0.9818)(11 \times 10^6)}

\phi_{C/D} = \dfrac{21600}{1079980}

\phi_{C/D} = 0.02 rad

To degree; we have

\phi_{C/D}  = 0.02 \times \dfrac{180}{\pi}

\mathbf{\phi_{C/D}  = 1.15^0}

3 0
3 years ago
A sprinter reaches his maximum speed in 2.5sec from rest with constant acceleration. He then maintains that speed and finishes t
liubo4ka [24]

The maximum Speed of the Sprinter from the velocity time graph of his motion is; 11.98 m/s

<h3>How to find the maximum speed?</h3>

We are given;

Initial Speed; u = 2.5 s

Total distance; d = 100 m

Total time; T = 9.6 s

The total distance is;

d = ¹/₂(9.6 + (9.6 - 2.5) * v

where v is maximum speed.

Thus;

¹/₂(9.6 + (9.6 - 2.5) * v = 100

16.7v = 200

v = 200/16.7

v = 11.98 m/s

Read more about Maximum Speed at; brainly.com/question/4931057

#SPJ1

3 0
2 years ago
Please help asap! I will give brainlist!
dexar [7]

Answer:

i did this this is b

Explanation:

7 0
3 years ago
Read 2 more answers
When comparing the distance of two stars from Earth, the star that is closer to Earth will be the dimmer star. True or false?
algol13

Answer:

False

Explanation:

The farther away a star is the dimmer it will appear.

4 0
3 years ago
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