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mihalych1998 [28]
3 years ago
13

Tech A says that the brake pedal uses leverage to multiply foot pressure. Tech B says that when braking hard while moving

Engineering
1 answer:
Nikolay [14]3 years ago
7 0

Tech- A is correct

Explanation:

  • Leverage is defined as using a tool to gain mechanical influence. The measure of the benefit gained depends on what kind of lever is used and how it is utilized.
  • Leverage is designed in such a way that it can reproduce the force from your leg many times before any force is transferred to brake fluid.
  • The brake pedal size and the measure of leverage received depends on the overall design of the brake system.
  • The second-order lever is used in the brake pedal. The brake pedal applies leverage to populate the force employed to the master cylinder. The effort needed to drive a load depends on the corresponding distance of the load and the work from the fulcrum. The proportion of load and work is known as mechanical advantage.
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How exactly do you do the rabbit in the hole loop on your shoe.
RideAnS [48]

Step 1- put shoe on
Step 2- grab the laces and cross them
Step 3- once you crossed them pick them back up and put one underneath one.
Step 4- tighten it then make two bunnies
Step 5- put on bunny over the other then loop it around
Step 6 pull the loops and bam you now know how to tie your shoes
4 0
2 years ago
What separates the work of technology transfer research from implementation of the products of such research?
tatuchka [14]

Answer:

The thing that separates the work of technology transfer research from implementation of the products of such research is:

Technology transfer research looks at how technology may be transferred but does not actually make the transfer.

Explanation:

This suggests that technology transfer research is different from the technology transfer (implementation) itself.  The first stops at making scientific investigations into technology transfer activities while the next step performs the actual transfer or implementation.  In other words, technology transfer conveys the results of scientific and technological research to the marketplace and to the wider society.  It is the bridge-builder between the research and the implementation.

4 0
2 years ago
Create a package named one_dimensional_array and write a class that completes the following "OneDimensionalArrays" class. You wi
yan [13]

Answer:

The filled in codes are

1) private static int[] arr;

2)  int arr[] = new int[size_of_array];

        int increment = 100;

        for (int i = 0; i < size_of_array; i++) {

       arr[i] = increment * i;

       }

      return arr;

3) for (int i = 0; i < myArray.length; i++) {

      System.out.println(myArray[i]);

4)  OneDimensionalArrays result = new OneDimensionalArrays();

    result.createIntegers(num);

    result.printArray(arr);

Explanation:

Create a package named one_dimensional_array and write a class that completes the following "OneDimensionalArrays" class. You will complete the class by filling in code wherever you see the comment:

//******* FILL IN CODE *********

import java.util.Scanner;

public class OneDimensionalArrays {

   

   int[] createIntegers(int size_of_array)

   {

      //*******  FILL IN CODE *********

      // Your code will create an array of ints as large as specified in size_of_array

      // Fill the array in with the values: 0, 100, 200, 300, ....

      // Return the array that you just created

   }

   void printArray(int[] myArray)

   {

      //*******  FILL IN CODE *********

       // Print out your array with one number per line.  Get the size of the

       // array from the "myArray" parameter (no hard coding the size)

   }

   public static void main(String[] args) {

       Scanner keyboard = new Scanner(System.in);

       

       System.out.println("Enter size of array to create: ");

       int num = keyboard.nextInt();

       //*******  FILL IN CODE *********

       // Construct an instance of the OneDimensionalArrays class

       // Using this object instance, call createIntegers to create

       // an array of integers.  Don't forget to save the results

       // Then call the printArray method to print out the contents

       // of your array.

       }

}

Completed Code when filled in looks this way below:

import java.util.Scanner;

public class OneDimensionalArrays {

  private static int[] arr;

  int[] createIntegers(int size_of_array) {

       int arr[] = new int[size_of_array];

       int increment = 100;

       for (int i = 0; i < size_of_array; i++) {

             arr[i] = increment * i;    

       }

       return arr;

   }

   void printArray(int[] myArray) {

       for (int i = 0; i < myArray.length; i++) {

           System.out.println(myArray[i]);          

       }

   }

   public static void main(String[] args) {

       Scanner keyboard = new Scanner(System.in);

       System.out.println("Enter size of array to create: ");

       int num = keyboard.nextInt();

       OneDimensionalArrays result = new OneDimensionalArrays();

       result.createIntegers(num);

       result.printArray(arr);

   }

}

7 0
3 years ago
How does an accelerometer work ?
LekaFEV [45]

Answer:

How an Accelerometer Works: When accelerometer is tilted, due to moving mass, alignment of capacitor plates changes which alters the capacitance value. These changes are measured by built in circuitry and outputs an analogue signal.

Explanation:

8 0
3 years ago
The lattice parameter of copper is 0.362 nanometer. The atomic weight of copper is 63.54 g/mole. Copper forms a fcc structure. A
Hatshy [7]

Answer:

a) 4.74 * 10^-23 cm^3

b)  8.9 g/cm^3

Explanation:

Given data :

Lattice parameter of copper = 0.362 nM

Atomic weight of copper = 63.54 g/mole

Given that copper forms a fcc structure

<u>a) Calculate the volume of the unit cell</u>

V = a^3

  = ( 0.362 * 10^-7  cm )^3 = 4.74 * 10^-23 cm^3

<u>b) Calculate density of copper in g/cm^3 </u>

Density = ( n*A ) / ( Vc * NA) ----------- ( 1 )

where: NA = Avogadro's number = 6.022 * 10^23  atoms/mol

n = number of atoms per unit cell = 4

A = atomic weight = 63.54 g/mol

Vc = volume of unit cell =  4.74 * 10^-23 cm^3

Input values into equation 1

Density = 8.9 g/cm^3

3 0
3 years ago
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