Which types of change observe the law of conservation of mass? single answer

Physics

2 answers:

guapka [62]3 years ago

4 0

D. Physical changes and chemical changes

Tems11 [23]3 years ago

4 0

Answer:

Explanation:

d just because it is and it's talking about mass and physical match's up with mass

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A 0.45 kg football traveling at a speed of 22 m/s is caught by a stationary receiver. If the football comes to a rest in the rec

joja [24]

Answer:

0.9Ns

Explanation:

Impulse formula is expressed as;

Impulse = Ft = m(v-u)

Impulse = m(v-u)

m is the mass of football = 0.45kg

v is the final velocity = 22m/s

u is the initial velocity = 0m/s

Impulse = 0.45(22-0)

Impulse = 0.45 * 22

Impulse = 0.9Ns

Hence the magnitude of the impulse imparted to the receiver by the ball is 0.9Ns

4 0

3 years ago

The terminals of a 0.70 Vwatch battery are connected by a 80.0-m-long gold wire with a diameter of 0.200 mm What is the current

Komok [63]

Answer:

$I=0.047A$

Explanation:

Let's use Ohm's law:

$V=IR$

$I=\frac{V}{R}$ (1)

Where:

$V=Voltage\\I=Current\\R=Electrical\hspace{2 mm}Resistance$

We know the value of the voltage V, so we need to find the value of R in order to find I. Fortunately there is a relation between the resistivity of a conductor and its electrical resistance given by:

$R=\rho*\frac{l}{A}$ (2)

Where:

$R=Electrical\hspace{2 mm}Resistance\\l=Length\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}conductor=80m\\A=Cross\hspace{2 mm}sectional\hspace{2 mm}area\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}conductor=1.256637061*10^{-7} \\\rho=Electrical\hspace{2 mm}resistivity\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}material=2.35*10^{-8}$

Keep in mind that the electrical resistivity of the gold is a known constant which is $\rho_g_o_l_d=2.35*10^{-8}$ and the cross sectional area of the conductor is calculated as: