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Neko [114]
3 years ago
5

As you move farther away from a source emitting a pure tone, the ___________ of the sound you hear decreases.

Physics
1 answer:
Colt1911 [192]3 years ago
7 0

Answer:

frequency

Explanation:

The phenomenon of apparent change in frequency due to the relation motion between the source and the observer is called Doppler's effect.

So, when we move farther, the frequency of sound decreases. The formula of the Doppler's effect is  

f' = \frac{v + v_o}{v+ v_s} f

where, v is the velocity of sound, vs is the velocity of source and vo is the velocity of observer, f is the true frequency. f' is the apparent frequency.

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If $1,800 is invested in a savings account offering interest at a rate of 4.5% per year, compounded continuously, how fast is th
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Answer:

The total amount  after 3 years is = $ 2054.10

Explanation:

Given data

Principal Amount (P) = $ 1800

Rate of interest (R) = 4.5 %

Thus the total amount after 3 years compounded annually is given by the formula =  P × [1 +\frac{R}{100}  ]^{3}

⇒ 1800 × [1 +\frac{4.5}{100}  ]^{3}

⇒ 2054.10

Thus the total amount  after 3 years is = $ 2054.10

Compound interest earned in three years = 2054.10 - 1800 = $ 254.10

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Pam is taking a train from the town of rome to the town of florence. rome is located 30 miles due west of the town of paris. flo
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What is the direction of magnetic field lines inside any magnet?
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17. Suppose you were standing on a scale in an elevator in free fall. What would the scale read?
lianna [129]

17

What would the scale read? zero

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5 0
3 years ago
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Find the moments of inertia Ix, Iy, I0 for a lamina that occupies the part of the disk x2 y2 ≤ 36 in the first quadrant if the d
Tasya [4]

Answer:

I(x)  = 1444×k ×{\pi}

I(y)  = 1444×k ×{\pi}

I(o) = 3888×k ×{\pi}  

Explanation:

Given data

function =  x^2 + y^2 ≤ 36

function =  x^2 + y^2 ≤ 6^2

to find out

the moments of inertia Ix, Iy, Io

solution

first we consider the polar coordinate (a,θ)

and polar is directly proportional to a²

so p = k × a²

so that

x = a cosθ

y = a sinθ

dA = adθda

so

I(x) = ∫y²pdA

take limit 0 to 6 for a and o to \pi /2 for θ

I(x) = \int_{0}^{6}\int_{0}^{\pi/2} y²p dA

I(x) = \int_{0}^{6}\int_{0}^{\pi/2} (a sinθ)²(k × a²) adθda

I(x) = k  \int_{0}^{6}a^(5)  da ×  \int_{0}^{\pi/2}  (sin²θ)dθ

I(x) = k  \int_{0}^{6}a^(5)  da ×  \int_{0}^{\pi/2}  (1-cos2θ)/2 dθ

I(x)  = k ({r}^{6}/6)^(5)_0 ×  {θ/2 - sin2θ/4}^{\pi /2}_0

I(x)  = k × ({6}^{6}/6) × (  {\pi /4} - sin\pi /4)

I(x)  = k ×  ({6}^{5}) ×   {\pi /4}

I(x)  = 1444×k ×{\pi}    .....................1

and we can say I(x) = I(y)   by the symmetry rule

and here I(o) will be  I(x) + I(y) i.e

I(o) = 2 × 1444×k ×{\pi}

I(o) = 3888×k ×{\pi}   ......................2

3 0
3 years ago
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