1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rama09 [41]
3 years ago
6

Calculate the ratio of ch3nh2 to ch3nh3cl required to create a buffer with ph = 10.28. express your answer using two significant

figures.
Chemistry
1 answer:
valentinak56 [21]3 years ago
8 0
Hello!

The chemical reaction for the ionization of CH₃NH₂ is the following:

CH₃NH₂ + H₂O ⇄ CH₃NH₃⁺ + OH⁻ pKb=3,30

pKa=14-pKb=14-3,30=10,70

Now we apply the Henderson-Hasselbach equation and clear for the ratio of CH₃NH₂ to CH₃NH₃Cl:

pH=pKa+log( \frac{[CH_3NH_2]}{[CH_3NH_3Cl]} ) \\  \\\frac{[CH_3NH_2]}{[CH_3NH_3Cl]}=  10^{(pH-pKa)}= 10^{(10,28-10,70)}=0,38

So, the ratio of CH₃NH₂ to CH₃NH₃Cl is 0,38

Have a nice day!
You might be interested in
A sample of paraffin wax undergoes the following change: C25H52(s) → C25H52(l)
nalin [4]

Answer:

Explanation:

(a) Answer: Intermolecular forces

The reason for this answer is because the substance (paraffin wax) only changed it's state from solid to liquid and didn't undergo a breakage in it's covalent bond within it's carbon chain which would have produced another substance.

(b) Solid substances are generally more dense than there corresponding liquid substances because the more compact particles are (which occurs in solids), the more dense they become. They are thus more dense than liquids because liquids have there particles loosely packed and well spaced making them less dense than there corresponding solids. Hence, the solid paraffin wax was going to become less dense because it's particles moved from being tightly packed (as solids) to being loosely packed (as liquids). Density refers to mass per volume but can also be described as the level of compactness of a substance. Thus, since liquid is not as compact as solid, it can be said to be less dense than solids.

5 0
3 years ago
Can some one tell me the best position in sex
masya89 [10]

Answer:

speedbump and magician

Explanation:

8 0
3 years ago
How many hydrogen atoms are in 3 molecules of ethyl alcohol, C2H3OH
Andrew [12]

Answer: 3 hydrogen atoms

Explanation: H=hydrogen

8 0
3 years ago
"To determine the amount of heroin in the mixture, you dissolve 1.00 g of the white powdery mixture in water in a 100.0-mL volum
UkoKoshka [18]

Explanation:

Formula to calculate osmotic pressure is as follows.

 Osmotic pressure = concentration × gas constant × temperature( in K)

Temperature = 25^{o} C

                      = (25 + 273) K

                      = 298.15 K  

Osmotic pressure = 531 mm Hg or 0.698 atm     (as 1 mm Hg = 0.00131)

Putting the given values into the above formula as follows.

       0.698 = C \times 0.082 \times 298.15 K


               C = 0.0285

This also means that,

  \frac{\text{moles}}{\text{volume (in L)}} = 0.0285

So,     moles = 0.0285 × volume (in L)

                      = 0.0285 × 0.100

                     = 2.85 \times 10^{-3
}

Now, let us assume that mass of C_{12}H_{23}O_{5}N = x grams

And, mass of C_{12}H{22}O_{11} = (1.00 - x)

So, moles of C_{12}H_{23}O_{5}N = \frac{mass}{\text{molar mass}}

                              = \frac{x}{369}

Now, moles of C_{12}H_{22}O_{11} = \frac{(1.00 - x)}{342}

                   = \frac{x}{369} + \frac{(1.00 - x)}{342}

                  = 2.85 \times 10^{-3}

             = x = 0.346

Therefore, we can conclude that amount of C_{12}H_{23}O_{5}N present is 0.346 g  and amount of C_{12}H_{22}O_{11} present is (1 - 0.346) g = 0.654 g.

4 0
3 years ago
I want to know the steps.
Artyom0805 [142]

The answer for the following problem is described below.

<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>

Explanation:

Given:

enthalpy of combustion of glucose(ΔH_{f} of C_{6}H_{12} O_{6}) =-1275.0

enthalpy of combustion of oxygen(ΔH_{f} of O_{2}) = zero

enthalpy of combustion of carbon dioxide(ΔH_{f} of CO_{2}) = -393.5

enthalpy of combustion of water(ΔH_{f} of H_{2} O) = -285.8

To solve :

standard enthalpy of combustion

We know;

ΔH_{f}  = ∈ΔH_{f} (products) - ∈ΔH_{f} (reactants)

C_{6}H_{12} O_{6} (s) +6 O_{2}(g) → 6 CO_{2} (g)+ 6 H_{2} O(l)

ΔH_{f} = [6 (-393.5) + 6(-285.8)] - [6 (0) + (-1275)]

ΔH_{f} = [6 (-393.5) + 6(-285.8)] - [0 - 1275]

ΔH_{f} = 6 (-393.5) + 6(-285.8)  - 0 + 1275

ΔH_{f} = -2361 - 1714 - 0 + 1275

ΔH_{f} =-2800 kJ

<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>

7 0
3 years ago
Other questions:
  • The question in the picture
    15·1 answer
  • What's a member of the boron family and the most abundant metal in the earths crust
    11·1 answer
  • Which factors would negatively impact the bodies digestive system
    6·1 answer
  • Write balanced molecular equation for the reaction between nitric acid and calcium hydroxide. Express your answer as a chemical
    8·1 answer
  • What effect does the use of an uncalibrated thermometer have on the boiling point?
    15·1 answer
  • You have arrived on a planet where S2, not O2, is the gas used as fuel in combustion reactions. When gaseous propane (C3H8) is b
    6·1 answer
  • When does the composition of a substance does not change?
    12·1 answer
  • I NEED HELP PLEASE, THANKS!
    12·1 answer
  • 3. Why are nutrients needed for living things? Describe the difference between living and nonliving things.
    15·1 answer
  • A student used a Vernier magnetic field sensor to measure the strength of the magnetic field generated by a bar magnet. At which
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!