Guys answer this pop quiz question it’s a joke btw it not real:) anyways here the pop quiz ok (Am walking my dog and the leashe
1 answer:
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Answer:
DeMorgan equivalent :
F = B + C
F' = ⁻B⁻+⁻C⁻ = ⁻BC⁻
Explanation:
Attached below is the logic gate implementation diagram and the DeMorgan equivalent Boolean statement as requested in part A and B
Answer:
The shear stress will be 80 MPa
Explanation:
Here we have;
τ = (T·r)/J
For rectangular tube, we have;
Average shear stress given as follows;
Where;
= 100 mm × 200 mm = 20000 mm² = 0.02 m²
t = Thickness of the shaft in question = 2 mm = 0.002 m
T = Applied torque
Therefore, 50 MPa = T/(2×0.002×0.02)
T = 50 MPa × 0.00008 m³ = 4000 N·m
Where the dimension is 50 mm × 250 mm, which is 0.05 m × 0.25 m
Therefore, = 0.05 m × 0.25 m = 0.0125 m².
Therefore, from the following average shear stress formula, we have;
Plugging in then values, gives;
The shear stress will be 80,000,000 Pa or 80 MPa.
Solution :
i. Slip plane (1 1 0)
Slip direction -- [1 1 1]
Applied stress direction = ( 1 0 0 ]
τ = 50 MPa ( Here slip direction must be perpendicular to slip plane)
τ = σ cos Φ cos λ
τ = σ cos Φ cos λ
∴
σ = 122.47 MPa
ii. Slip plane --- (1 1 0)
Slip direction -- [1 1 1]
τ = σ cos Φ cos λ
∴
σ = 122.47 MPa
iii. Slip plane --- (1 0 1)
Slip direction --- [1 1 1]
τ = σ cos Φ cos λ
∴
σ = 122.47 MPa
iv. Slip plane -- (1 0 1)
Slip direction ---- [1 1 1]
τ = σ cos Φ cos λ
∴
σ = 122.47 MPa
∴ (1, 0, -1). (1, -1, 1) = 1 + 0 - 1 = 0