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Temka [501]
3 years ago
13

Please select the word from the list that best fits the definition Vibrations that move through the ground carrying the energy r

eleased during an earthquake are called ______.
Chemistry
2 answers:
ZanzabumX [31]3 years ago
3 0
<h2>Answer : Seismic Waves.</h2><h2 /><h3>Explanation : </h3><h3>Vibrations that move through the ground carrying the energy released during an earthquake are called seismic waves.</h3>

Seismic waves are waves of energy which usually travels through the Earth's layers, and as a result release the energy during earthquakes, volcanic eruptions, magma movement, large landslides or large man-made explosions. It is mainly measured through a special instrument called as seismometer and the graph obtained is called as seismograph.

vichka [17]3 years ago
3 0

Vibrations that move through the ground carrying the energy released during an earthquake are called ______. (seismic waves

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Which metal will gain heat faster. Brass or Gold?
FinnZ [79.3K]
Hey!!

here is your answer >>>

In order to find out which metal gains heat faster, we will have to find out their specific heat!. Specific heat is the heat required to raise the temperature of the unit substance, The specific heat of gold and brass are 0.126 for gold and 0.380 for brass!. The specific heat of gold is less than brass!. So, gold will gain heat faster!.

Hope my answer helps!
5 0
2 years ago
Read 2 more answers
Use the given data at 500 K to calculate ΔG°for the reaction
Anton [14]

Answer : The  value of \Delta G^o for the reaction is -959.1 kJ

Explanation :

The given balanced chemical reaction is,

2H_2S(g)+3O_2(g)\rightarrow 2H_2O(g)+2SO_2(g)

First we have to calculate the enthalpy of reaction (\Delta H^o).

\Delta H^o=H_f_{product}-H_f_{reactant}

\Delta H^o=[n_{H_2O}\times \Delta H_f^0_{(H_2O)}+n_{SO_2}\times \Delta H_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta H_f^0_{(H_2S)}+n_{O_2}\times \Delta H_f^0_{(O_2)}]

where,

\Delta H^o = enthalpy of reaction = ?

n = number of moles

\Delta H_f^0 = standard enthalpy of formation

Now put all the given values in this expression, we get:

\Delta H^o=[2mole\times (-242kJ/mol)+2mole\times (-296.8kJ/mol)}]-[2mole\times (-21kJ/mol)+3mole\times (0kJ/mol)]

\Delta H^o=-1035.6kJ=-1035600J

conversion used : (1 kJ = 1000 J)

Now we have to calculate the entropy of reaction (\Delta S^o).

\Delta S^o=S_f_{product}-S_f_{reactant}

\Delta S^o=[n_{H_2O}\times \Delta S_f^0_{(H_2O)}+n_{SO_2}\times \Delta S_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta S_f^0_{(H_2S)}+n_{O_2}\times \Delta S_f^0_{(O_2)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S_f^0 = standard entropy of formation

Now put all the given values in this expression, we get:

\Delta S^o=[2mole\times (189J/K.mol)+2mole\times (248J/K.mol)}]-[2mole\times (206J/K.mol)+3mole\times (205J/K.mol)]

\Delta S^o=-153J/K

Now we have to calculate the Gibbs free energy of reaction (\Delta G^o).

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

At room temperature, the temperature is 500 K.

\Delta G^o=(-1035600J)-(500K\times -153J/K)

\Delta G^o=-959100J=-959.1kJ

Therefore, the value of \Delta G^o for the reaction is -959.1 kJ

3 0
2 years ago
A chemistry student needs 60.0 g of tetrahydrofuran for an experiment. By consulting the CRC Handbook of Chemistry and Physics,
Evgen [1.6K]

Answer:

67.492cm^3

Explanation:

To get the volume of tetrahydrofuran needed, what the student need to do is to apply mathematical calculations.

We know quite well that to obtain the volume of a substance, given the mass of the substance and the density of the substance is possible.

The volume of the substance is simply the mass of the substance divided by the density of the substance.

This is thus volume = mass/density

The mass given is the question is 60g while the density given is 0.889g/cm^3

The volume = 60/0.889 = 67.492cm^3

8 0
2 years ago
If an object with a volume of 105 mL and a density of 0.801 g/mL, what is the objects mass?
garik1379 [7]

Answer:

The objects mass is 84, 105 g. See the explanation below, please.

Explanation:

We use the formula:

Density= mass/volume

Mass= Density x volume =0.801 g/mL x 105 mL = 84, 105 g

6 0
2 years ago
Aqueous solutions of Na2CO3 and Ca(NO3)2, 0.10 M each, are combined. A white precipitate is observed in the container after mixi
anzhelika [568]

The question is incomplete. Here is the complete question.

Aqueous solutions of Na_{2}CO_{3} and Ca(NO_{3})_{2}, 0.10 M each, are combined. A white precipitate is observed in the container after mixing. he precipitate is filtered andcarefully rinsed with distilled water to remove other ions. A sample of the precipitate is added to 100 mL of 0.1 M NaCl. A second sample of the precipitate is then added to 100 mL of 0.1 M HCl. What would be observed in each case?

                 Observation upon                                         Observation upon

               addition of precipitate                                  addition of precipitate

                      to NaCl(aq)                                                       to HCl(aq)

(A)     additional precipitates forms                        no visible reaction occurs

(B)     no visible reaction occurs                            gas is produced and some                                                                                        precipitate dissolves

(C)     no visible reaction occurs                             no visible reaction occurs

(D)     additional precipitates forms                       gas is produced and some

                                                                                    precipitate dissolves

Answer: (B) No visible reaction occurs; Gas is produced and some precipitate dissolves

Explanation: When aqueous solutions of Na_{2}CO_{3} and Ca(NO_{3})_{2} are combined, it reacts according to the following balanced equation:

Na_{2}CO_{3}+Ca(NO_{3})_{2} → CaCO_{3}_{(s)}+2NaNO_{3}_{(aq)}

forming calcium carbonate (CaCO_{3}), which, as it is insoluble in water, precipitates as a solid of the color white. This process is <u>Precipitation</u> and this reaction is a <u>Precipitation</u> <u>Reaction</u>.

When calcium carbonate reacts with NaCl it produces:

CaCO_{3}+2NaCl → CaCl_{2}+Na_{2}CO_{3}

Now, calcium chloride is an inorganic compound very soluble in water, so, in this reaction, there are no precipitate and <u>no visible reaction occurs</u>.

When CaCO_{3} reacts with hydrochloridric acid, the balanced reaction is

CaCO_{3}+2HCl → CaCl_{2}+H_{2}CO_{3}

which, also produces calcium chloride and carbonic acid.

Both are soluble in water but, when carbonic acid is in an "aqueous state", carbonic acid, it dissociates, forming carbon dioxide and water. Therefore, <u>gas is produced and some precipitate dissolves</u>.

In conclusion, sentence B is the correct alternative.

5 0
3 years ago
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