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Temka [501]
4 years ago
13

Please select the word from the list that best fits the definition Vibrations that move through the ground carrying the energy r

eleased during an earthquake are called ______.
Chemistry
2 answers:
ZanzabumX [31]4 years ago
3 0
<h2>Answer : Seismic Waves.</h2><h2 /><h3>Explanation : </h3><h3>Vibrations that move through the ground carrying the energy released during an earthquake are called seismic waves.</h3>

Seismic waves are waves of energy which usually travels through the Earth's layers, and as a result release the energy during earthquakes, volcanic eruptions, magma movement, large landslides or large man-made explosions. It is mainly measured through a special instrument called as seismometer and the graph obtained is called as seismograph.

vichka [17]4 years ago
3 0

Vibrations that move through the ground carrying the energy released during an earthquake are called ______. (seismic waves

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Enter your answer in the provided box. A person's blood alcohol (C2H5OH) level can be determined by titrating a sample of blood
Annette [7]

<u>Answer:</u> The mass percent of alcohol in blood is 0.183 %

<u>Explanation:</u>

To calculate the moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of Cr_2O_7^{2-} solution = 0.05961 M

Volume of solution = 35.46 mL = 0.03546 L   (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

0.05961M=\frac{\text{Moles of }Cr_2O_7^{2-}}{0.03546L}\\\\\text{Moles of }Cr_2O_7^{2-}=(0.05961mol/L\times 0.03546L)=2.11\times 10^{-3}mol

The given chemical reaction follows:

16H^+(aq.)+2Cr_2O_7^{2-}(aq.)+C_2H_5OH(aq.)\rightarrow 4Cr^{3+}(aq.)+2CO_2(g)+11H_2O(l)

By Stoichiometry of the reaction:

2 moles of dichromate ions react with 1 mole of ethanol.

So, 2.11\times 10^{-3}mol of dichromate ions will react with = \frac{1}{2}\times 2.11\times 10^{-3}=1.06\times 10^{-3}mol

  • To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of ethanol = 1.06\times 10^{-3}mol

Molar mass of ethanol = 46.07 g/mol

Putting values in above equation, we get:

1.06\times 10^{-3}mol=\frac{\text{Mass of ethanol}}{46.07g/mol}\\\\\text{Mass of ethanol}=(1.06\times 10^{-3}mol\times 46.07g/mol)=0.0488g

  • To calculate the mass percent of ethanol in blood, we use the equation:

\text{Mass percent of ethanol}=\frac{\text{Mass of ethanol}}{\text{Mass of blood plasma}}\times 100

Mass of blood plasma = 26.60 g

Mass of ethanol = 0.0488 g

Putting values in above equation, we get:

\text{Mass percent of ethanol}=\frac{0.0488g}{26.60g}\times 100=0.183\%

Hence, the mass percent of alcohol in blood is 0.183 %

5 0
3 years ago
The measured value 24.00 g has an uncertainty of?
Orlov [11]

Answer:

±0.005 g

Explanation:

The uncertainty depends on whether the measurement was obtained manually or digitally.

1. Manual

The minimum uncertainty is ±0.01 g.

It may be greater, depending on random or personal errors

2. Digital

Most measurements of mass are now made on digital scales.

A digital device must always round off the measurement it displays.

For example, if the display reads 20.00, the measurement must be between 20.005 and 19.995 (±0.005).

If the measured value were 20.006, the display would round up to 20.01.

If the measured value were 19.994, the display would round down to 19.99.

The uncertainty is ±0.005 g.

The scale shown below would display a mass of 20.00 g

6 0
4 years ago
What are the two homologous structures?
photoshop1234 [79]
<span>analogous and <span>homologous</span></span>
4 0
4 years ago
A high pich always correspond to
Masteriza [31]
A high frequency sound wave 
4 0
4 years ago
A 5.00 liter gas sample is collected at a temperature and pressure of 27.0 degree C and 1.20 atm. It is desired to transfer the
kipiarov [429]

Answer:

The temperature of the gas in the 3.00 liter container, must be 150K

Explanation:

Let's apply the Ideal Gas Law, to find out the moles

P . V = n . R . T

1,20 atm . 5L = n . 0,082 L.atm/mol.K . 300 K

(1,20 atm . 5L) /  (0,082 mol.K/L.atm . 300 K) = n

6/24,6 mol = n = 0,244 moles

We have the moles now, so let's find the temperature in our new conditions.

P . V = n . R . T

1 atm . 3L = 0,244 moles . 0,082 L.atm/mol.K . T° in K

(1 atm . 3L / 0,244 moles . 0,082 mol.K/L.atm) = T° in K

3/20,008 K = T° in K = 150K

3 0
3 years ago
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