Answer:
C. More NO2 and SO2 will form
Explanation:
Le Chatelier's Principle : It predicts the behavior of equilibrium due to change in pressure , temperature , volume , concentration etc
It states that When external changes are introduced in the equilibrium then it will shift the equilibrium in a direction to reduce the change.
In given Reaction SO3 is introduced(increased) .
So equilibrium will shift in the direction where SO3 should be consumed(decreased)
Hence the equilibrium will go in backward direction , i.e
![NO + SO_{3} \rightarrow NO_{2} + SO_{2}](https://tex.z-dn.net/?f=NO%20%2B%20SO_%7B3%7D%20%5Crightarrow%20NO_%7B2%7D%20%2B%20SO_%7B2%7D)
So more and more Of NO2 and SO2 will form
Answer:
The half-cells separate the oxidation half-reaction from the reduction half-reaction and make it possible for current to flow through an external wire.
Explanation:
1. 3.0% ----> 3.0 kg fat= 100 kg body weigh
also remember that 1 kg= 2.20 lbs
![65 kg \frac{3.0 kg}{100 kg} x \frac{2.20 lb}{1 kg} = 4.29 lbs](https://tex.z-dn.net/?f=65%20kg%20%20%5Cfrac%7B3.0%20kg%7D%7B100%20kg%7D%20x%20%20%5Cfrac%7B2.20%20lb%7D%7B1%20kg%7D%20%3D%204.29%20lbs)
2. 0.94 g/mL----> 0.94 grams= 1 mL
1 Liters= 1000 mL
1kg= 1000 grams
Answer: 159 grams
Explanation:
Copper (ii) oxide has the chemical formula CuO.
Now given that:
Mass of CuO in grams = ? (let unknown value be Z)
Number of moles = 2.00 moles
Molar mass of CuO = ?
For the molar mass of CuO: Atomic mass of Copper = 63.5g ; Oxygen = 16g
= 63.5g + 16g
= 79.5 g/mol
Apply the formula:
Number of molecules = (mass in grams/molar mass)
2.00 moles = (Z / 79.5 g/mol)
Z = 79.5 g/mol x 2.00 moles
Z = 159g
Thus, there are 159 grams in 2.00 moles of copper (ii) oxide
heating is repeated to ensure all water molecules have evaporated