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Lerok [7]
3 years ago
14

Theories are built upon testing many ________?A).laws.B).Hypothese.C).Facts.​

Chemistry
2 answers:
Delicious77 [7]3 years ago
7 0

Answer:

B. Hypothese

Explanation:

jeyben [28]3 years ago
5 0

Answer:

B.Hypothese

Explanation:

i don't know but that's first came in my mind

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Scientist use alternative ways to seek out if a fault is active which one isn't include​
dalvyx [7]

Answer:

Geologists commonly consider faults to be active if there has been movement observed or evidence of seismic activity during the last 10,000 years. Active faulting is considered to be a geologic hazard - one related to earthquakes as a cause.

Explanation:

Plz mark brainliest thanks

3 0
2 years ago
Assume that instead of Taq polymerase, another polymerase, one that is very heat-sensitive, was used in a PCR. What differences
frez [133]

Answer:

Taq polymerase is a thermostable which states that it can even work at higher temperature. The main function of using this enzyme is that it is used to amplify the DNA which will help in producing ample amount of DNA sample.

The enzyme activity is temperature dependent. The denaturation and annealing steps of the PCR occurs at very high temperature.

Any other enzyme used at such an high temperature would have decreased the enzyme activity and the procedure would not be completed.

7 0
3 years ago
If the take off velocity of an airplane on a runway is 300 km /hr with an acceleration of 1 m/s2. What is the take off time of t
Rama09 [41]
<h3>Answer:</h3>

83.33 seconds.

<h3>Explanation:</h3>

<u>We are given;</u>

  • Take off velocity as 300 km/hr
  • Acceleration as 1 m/s²

We are required to calculate the take off time of the airplane.

<h3>Step 1: Convert velocity from km/hr to m/s </h3>

We are going to use the conversion factor.

The conversion factor is 3.6 km/hr per m/s

Therefore;

Velocity = 300 km/hr ÷ 3.6 km/hr per m/s

             = 83.33 m/s

<h3>Step 2: Calculate the take off time</h3>

We know that;

v = u + at

where, u is the initial velocity, v the final velocity, a the acceleration and t is time.

But, initial velocity is Zero

Therefore;

83.33 m/s = 1 m/s² × t

Thus;

time = 83.33 m/s ÷ 1 m/s²

       = 83.33 seconds

Therefore, the take off time is 83.33 seconds.

5 0
2 years ago
Which term represents the movement of molecules from an area of lower concentration to one of higher concentration with carrier
poizon [28]

Answer:

Active transport

Explanation:

Active transport is defined as the movement of ions or molecules from a region of lower concentration into a region of higher concentration by the use of energy. Two examples of active transport include the uptake of glucose in human intestine and the absorption of mineral ions into plant roots.

Active transport requires energy because it involves the movement of molecules against an existing concentration gradient.

4 0
2 years ago
Which is true of ultraviolet rays?
Ket [755]
A is true of UV rays.
B is true not of UV rays but rather of visible light.
C is true not of UV rays but rather of microwaves. (unless you actually toast your toast in a toaster like a normal person)
D is true not of UV rays but rather of radio waves.
7 0
3 years ago
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