Need answer for 9.0mm x 2.0mm x 2.0mm
1 answer:
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Answer:
0.444 mol/L
Explanation:
First step is to find the number of moles of oxalic acid.
n(oxalic acid) =
Now use the molar ratio to find how many moles of NaOH would be required to neutralize of oxalic acid.
n(oxalic acid): n(potassium hydroxide)
1 : 2 (we get this from the balanced equation)
: x
x = 0.0111 mol
Now to calculate what concentration of KOH that would be in 25 mL of water:
Answer:
Explanation:
first write the equilibrium equaion ,
⇄
assuming degree of dissociation =1/10;
and initial concentraion of =c;
At equlibrium ;
concentration of
is very small so
can be neglected
and equation is;
=
composiion ;