Answer:
None of the options are correct.
The correct answer is 1.10g
Explanation:
First, we'll begin by balancing the equation given above. This is illustrated below:
2HCl + 2Na —> 2NaCl + H2
Next, let us calculate the mass of HCl that reacted and the mass of H2 produced from the balanced equation. This is illustrated below:
Molar Mass of HCl = 1 + 35.5 = 36.5g/mol
Mass of HCl from the balanced equation = 2 x 36.5 = 73g
Molar Mass of H2 = 2x1 = 2g/mol
Now we can easily find the mass of H2 produced when 40g of HCl reacted as shown below:
From the balanced equation,
73g of HCl produced 2g of H2.
Therefore, 40g of HCl will produce = (40 x 2)/73 = 1.10g of H2.
From the calculations made above,
40g of HCl produced 1.10g of H2
Answer:
(E) changing temperature
Explanation:
Consider the following reversible balanced reaction:
aA+bB⇋cC+dD
If we know the molar concentrations of each of the reaction species, we can find the value of Kc using the relationship:
Kc = ([C]^c * [D]^d) / ([A]^a * [B]^b)
where:
[C] and [D] are the concentrations of the products in the equilibrium; [A] and [B] reagent concentrations in equilibrium; already; b; c and d are the stoichiometric coefficients of the balanced equation. Concentrations are commonly expressed in molarity, which has units of moles / 1
There are some important things to remember when calculating Kc:
- <em>Kc is a constant for a specific reaction at a specific temperature</em>. If you change the reaction temperature, then Kc also changes
- Pure solids and liquids, including solvents, are not considered for equilibrium expression.
- The reaction must be balanced with the written coefficients as the minimum possible integer value in order to obtain the correct value of Kc
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