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3 years ago

What is the current in a 160 V circuit if the resistance is 2 ohms?

Physics

2 answers:

Leto [7]3 years ago

7 0

Answer:

Question: What is the current in a 160V circuit if the resistance is 2Ω?

Answer:

Voltage ( V ) = 160V

Resistance ( R ) = 2Ω

Current ( I ) = ?

By Ohms law

⇒ V = IR

⇒ 160 = I × 2

⇒ I = 160 / 2 = 80A

\rule{200}2

Question: What is the current in a 160V circuit if the resistance is 20Ω?

Answer:

Voltage ( V ) = 160V

Resistance ( R ) = 20Ω

Current ( I ) = ?

By Ohms law

⇒ V = IR

⇒ 160 = I × 20

⇒ I = 160 / 20 = 8A

\rule{200}2

Question: What is the current in a 160V circuit if the resistance is 10Ω?

Answer:

Voltage ( V ) = 160V

Resistance ( R ) = 10Ω

Current ( I ) = ?

By Ohms law

⇒ V = IR

⇒ 160 = I × 10

⇒ I = 160 / 10 = 16A

\rule{200}2

Question: Based on questions 2, 3, and 4, what happens to the current in a circuit as the resistance decreases? Increases?

Answer:

From ohms law

⇒ I = V / R

If we take Voltage as proportionality constant

⇒ I ∝ 1 / R

So, we can conclude that current is inversely proportional to resistance.

From 2, 3, 4 questions we can conclude that,

If resistance increases, current decreases and when resistance decreases, current increases.

\rule{200}2

Question: What voltage is required to move 6A through 5Ω?

Answer:

Resistance ( R ) = 5Ω

Current ( I ) = 6A

Voltage ( V ) = ?

By Ohms law

⇒ V = IR

⇒ V = 6 × 5

⇒ V = 30V

\rule{200}2

Question: What voltage is required to move 6A through 10Ω?

Answer:

Resistance ( R ) = 10Ω

Current ( I ) = 6A

Voltage ( V ) = ?

By Ohms law

⇒ V = IR

⇒ V = 6 × 10

⇒ V = 60V

\rule{200}2

Question:What voltage is required to move 6A through 20Ω?

Answer:

Resistance ( R ) = 20Ω

Current ( I ) = 6A

Voltage ( V ) = ?

By Ohms law

⇒ V = IR

⇒ V = 6 × 20

⇒ V = 120V

\rule{200}2

erica [24]3 years ago

7 0

Answer:

80 amps

Explanation:

V = IR

160 volts = I(2 ohms)

I = 80 amps

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For a damped simple harmonic oscillator, the block has a mass of 1.2 kg and the spring constant is 9.8 N/m. The damping force is

ArbitrLikvidat [17]

Answer:

a) t=24s

b) number of oscillations= 11

Explanation:

In case of a damped simple harmonic oscillator the equation of motion is

m(d²x/dt²)+b(dx/dt)+kx=0

Therefore on solving the above differential equation we get,

x(t)=A₀ $e^{\frac{-bt}{2m}}cos(w't+\phi)=A(t)cos(w't+\phi)$

where A(t)=A₀ $e^{\frac{-bt}{2m}}$

A₀ is the amplitude at t=0 and

$w'$ is the angular frequency of damped SHM, which is given by,

$w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }$

Now coming to the problem,

Given: m=1.2 kg

k=9.8 N/m

b=210 g/s= 0.21 kg/s

A₀=13 cm

a) A(t)=A₀/8

⇒A₀ $e^{\frac{-bt}{2m}}$ =A₀/8

⇒ $e^{\frac{bt}{2m}}=8$

applying logarithm on both sides

⇒ $\frac{bt}{2m}=ln(8)$

⇒ $t=\frac{2m*ln(8)}{b}$

substituting the values

$t=\frac{2*1.2*ln(8)}{0.21}=24s(approx)$

b) $w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }$

$w'=\sqrt{\frac{9.8}{1.2}-\frac{0.21^{2}}{4*1.2^{2}}}=2.86s^{-1}$

$T'=\frac{2\pi}{w'}$ , where $T'$ is time period of damped SHM

⇒ $T'=\frac{2\pi}{2.86}=2.2s$

let $n$ be number of oscillations made

then, $nT'=t$

⇒ $n=\frac{24}{2.2}=11(approx)$

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3 years ago

The collision between a hammer and a nail can be considered to be approximately elastic. estimate the kinetic energy acquired by

Setler [38]

Here we can use momentum conservation as in this type of collision there is no external force on it

$m_1v_{1i} + m_2v_{2i} = m_1 v_{1f} + m_2v_{2f}$

now here we can say

$m_1 = 10 g$

$v_{1i} = 0$

$m_2 = 550 g$

$v_{2i} = 3.5 m/s$

now here we can say

$10*0 + 550 * 3.5 = 10 v_{1f} + 550 v_{2f}$

$192.5 = v_{1f} + 55 v_{2f}$

now by coefficient of restitution

for elastic collision we know that e = 1

$v_{2f} - v_{1f} = e(v_{1i} - v_{2i})$

$v_{2f} - v_{1f} = 0 - 3.5$

now by solving the two equation

$56v_{2f} = 189$

$v_{2f} = 3.375 m/s$

also we know that

$v_{1f} = v_{2f} + 3.5 = 3.375 + 3.5 = 6.875 m/s$

so final speed of the nail is 6.875 m/s

6 0

3 years ago

Read 2 more answers

How do u answer this?

gayaneshka [121]

Answer:

food

Explanation:

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4 0

3 years ago

What are the unit for acceleration

Flura [38]

<h3>Answer</h3>

m/s^2 (meter per sec square)

Explanation:

acc = change in velocity/time

= distance/time

----------------

time

= m/s

------

=m/s^2

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3 years ago

Identify trends in physical properties based on intermolecular forces

umka21 [38]

The Boiling point,melting point, surface tension and viscousity will increase while the Vapor pressure will decrease.

<h3 /><h3>What are intermolecular forces?</h3>

Intermolecular forces are the forces that bind two molecules together. Physical properties are affected by the strength of intermolecular forces

An increase in the strength of intermolecular forces increases will lead to an increase in force applied to break the barriers posed by the strength of the molecules.

This increased intermolecular strength will cause a rise in boiling point,melting point, viscousity and surface tension.

The Vapor pressure reduces with increasing intermolecular strength. Vapor pressure is the amount of vapor that is equilibrium with its own liquid or solid. Hence,with increasing intermolecular strength the amount of vapor that is in equilibrium with its own liquid will reduce.

To know more about intermolecular forces follow

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2 years ago