Answer:
The solution will turn red.
Explanation:
HC₁₄H₁₄SO₃ + H₂O ⇌ HC₁₄H₁₄SO₃⁻ +H₃O⁺
(red) (yellow)
Methyl orange is a weak acid in which the ionized and unionized forms are distinct colours and are in equilibrium with each other,
At about pH 3.4, the two the forms are present in equal amounts, and the indicator colour is orange.
If you add more acid, you are disturbing the equilibrium.
According to Le Châtelier's Principle, when you apply a stress to a system at equilibrium, it will respond in such a way as to relieve the stress.
The system will try to get rid of the added acid, so the position of equilibrium will move to the left.
More of the unionized molecules will form, so the solution will turn red.
The Correct Answer Is 3.2
Answer:
It would be True
Explanation:
Because they both have the same push of gravity. Gravity affects all objects equally. If you drop an egg and a watermelon at the same time they would both collide with the floor at the same time.
Answer:
2H₂ + O₂ → 2H₂O
Explanation:
Chemical equation:
H₂ + O₂ → H₂O
Balance chemical equation:
2H₂ + O₂ → 2H₂O
Step 1:
H₂ + O₂ → H₂O
Left hand side Right hand side
H = 2 H = 2
O = 2 O = 1
Step 2:
H₂ + O₂ → 2H₂O
Left hand side Right hand side
H = 2 H = 4
O = 2 O = 2
Step 3:
2H₂ + O₂ → 2H₂O
Left hand side Right hand side
H = 4 H = 4
O = 2 O = 2
Explanation:
The given data is as follows.
= 0.483, ![[Co^{3+}]](https://tex.z-dn.net/?f=%5BCo%5E%7B3%2B%7D%5D)
= 0.173 M,
![[Co^{2+}]](https://tex.z-dn.net/?f=%5BCo%5E%7B2%2B%7D%5D)
= 0.433 M, ![[Cl^{-}]](https://tex.z-dn.net/?f=%5BCl%5E%7B-%7D%5D)
= 0.306 M,
= 9.0 atm
According to the ideal gas equation, PV = nRT
or, P = 
Also, we know that
Density = 
So, P = MRT
and, M = 
= 
= 
= 0.368 mol/L
Now, we will calculate the cell potential as follows.
E = ![E^{o} - \frac{0.0591}{n} log \frac{[Co^{2+}]^{2}[Cl_{2}]}{[Co^{3+}][Cl^{-}]^{2}}](https://tex.z-dn.net/?f=E%5E%7Bo%7D%20-%20%5Cfrac%7B0.0591%7D%7Bn%7D%20log%20%5Cfrac%7B%5BCo%5E%7B2%2B%7D%5D%5E%7B2%7D%5BCl_%7B2%7D%5D%7D%7B%5BCo%5E%7B3%2B%7D%5D%5BCl%5E%7B-%7D%5D%5E%7B2%7D%7D)
= 
= 
= 
= 0.483 - 0.0185
= 0.4645 V
Thus, we can conclude that the cell potential of given cell at 
is 0.4645 V.
