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Tamiku [17]
3 years ago
10

Draw the products formed from 2-methyl-2-butene by sequences (1.) and (2.). hydroboration followed by oxidation with alkaline hy

drogen peroxide. acid-catalyzed hydration. You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. Product of sequence 1:

Chemistry
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

product won't form hydrogen bond with water

Explanation:

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Why is a thermos considered a (mostly) closed system? Question 3 options: different types of liquids stay hot thermoses come in
cestrela7 [59]

Answer:

Different types of hot or cold items can be stored in a thermos and power cannot enter or exit the system when the thermos lid is tightly closed

Explanation:

Closed systems are those that do not interact or do not exchange energy with the environment that surrounds them, that is why internal temperatures and conditions are maintained.

The human body is an open system, that is, it would be the opposite of the thermos since we constantly exchange energy with the environment through sweating, emission of gases, urine, feces, and the ingestion of food.

Thermoses are systems specially created to maintain a medium, it will be maintained if its lid is hermetically closed to prevent heat leakage or entry in situations of cold fluids.

4 0
3 years ago
Please help me the picture is above.
Andreas93 [3]

Answer:

A

Explanation:

bc inorganic compoud refers to all compound that do not contain carbons.

4 0
3 years ago
How many moles of CO gas are in 34.6 L?
Troyanec [42]

moles of CO gas : 1.545

<h3>Further explanation</h3>

Standard conditions for temperature and pressure are used as a reference in certain calculations or conditions

There are 2 conditions that are usually used as a reference : STP and RTP

Assuming the STP state :

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

Then for 34.6 L of CO gas :

\tt moles=\dfrac{34.6}{22.4}=1.545

6 0
2 years ago
A 52.0 mL portion of a 1.20 M solution is diluted to a total volume of 278 mL. A 139 mL portion of that solution is diluted by a
RoseWind [281]

Answer:

C_3=0.125M

Explanation:

Hello!

In this case, we can divide the problem in two steps:

1. Dilution to 278 mL: here, the initial concentration and volume are 1.20 M and 52.0 mL respectively, and a final volume of 278 mL, it means that the moles remain the same so we can write:

V_1C_1=V_2C_2

So we solve for C2:

C_2=\frac{C_1V_1}{V_2}=\frac{52.0mL*1.20M}{278mL}\\\\C_2=0.224M

2. Now, since 111 mL of water is added, we compute the final volume, V3:

V_3=139+111=250mL

So, the final concentration of the 139 mL portion is:

C_3=\frac{139 mL*0.224M}{250mL}\\\\C_3=0.125M

Best regards!

8 0
3 years ago
In what sense are photons quantized?
lara [203]

Answer:

D. Each photon has a specific amount of energy​

Explanation:

5 0
2 years ago
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