Draw the products formed from 2-methyl-2-butene by sequences (1.) and (2.). hydroboration followed by oxidation with alkaline hy
drogen peroxide. acid-catalyzed hydration. You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. Product of sequence 1:
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I used the genetic code table. mRNA codon ===> amino acid
1st base 2nd base 3rd base
A U U ===> Isoleucine
A U C ===> Isoleucine
The point mutation of codon AUU to AUC is a neutral mutation because it neither benefits nor deter the ability of the organism to survive and reproduce.
As you can see, Both codons result to the Isoleucine amino acid.
Another codon that will still result to the Isoleucin amino acid is AUA.
1st base 2nd base 3rd base
A U U ===> Isoleucine
A U C ===> Isoleucine
The point mutation of codon AUU to AUC is a neutral mutation because it neither benefits nor deter the ability of the organism to survive and reproduce.
As you can see, Both codons result to the Isoleucine amino acid.
Another codon that will still result to the Isoleucin amino acid is AUA.