3 years ago

Why was Bohr’s atomic model replaced by the modern atomic model ?

Physics

1 answer:

Alex Ar [27]3 years ago

5 0

Answer:

a military base with aliens simple

Explanation:

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A motorcycle slows down uniformly from a speed of 21 m/s to rest in 6.0s. How far did it travel during this time?

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Answer:

63 m

Explanation:

The initial velocity of the motorcycle is

$v_i = 21 m/s$

The final velocity is

$v_f = 0$

And the time taken is

$t=6.0 s$

Since the acceleration of the motorcycle is uniform, we can find the distance traveled by the motorcycle during this time by using the following SUVAT equation:

$S=\frac{1}{2} (v_i +v_f) t$

Substituting numbers into the equation, we find

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Red light of wavelength 630 nm passes through two slits and then onto a screen that is 1.4 m from the slits. The center of the 3

VARVARA [1.3K]

Answer:

Part a)

$f = 4.76 \times 10^{14} Hz$

Part b)

$d = 3.48 \times 10^{-4} m$

Part c)

$\theta = 0.311 degree$

Explanation:

Part a)

As we know that the speed of light is given as

$c = 3 \times 10^8 m/s$

$\lambda = 630 nm$

now the frequency of the light is given as

$f = \frac{c}{\lambda}$

so we have

$f = \frac{3 \times 10^8}{630 \times 10^{-9}}$

$f = 4.76 \times 10^{14} Hz$

Part b)

Position of Nth maximum intensity on the screen is given as

$y_n = \frac{n\lambda L}{d}$

so here we know for 3rd order maximum intensity

$y_3 = 0.76 cm$

n = 3

L = 1.4 m

$0.76 \times 10^{-2} = \frac{3(630 \times 10^{-9})(1.4)}{d}$

$d = 3.48 \times 10^{-4} m$

Part c)

angle of third order maximum is given as

$d sin\theta = 3 \lambda$

$3.48 \times 10^{-4} sin\theta = 3(630 \times 10^{-9})$

$\theta = 0.311 degree$

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directly, inversely ... newton's grav eqn

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