Answer:
a. f₀ = 6.355 Hz ; b. Δf = 6.35 Hz
Explanation:
Given Data:
Length of wire = l =347 m ;
Tension in wire = T = 65.2 * 10⁶N ;
Linear density = μ = 3.35 kg/m ;
Solution:
a)
Fundamental mode = f₀ = (1/2l)*(sqr.root(T/μ))
By putting the values, we get
f₀ = (1/2(347))*
f₀ = 6.355 Hz
b)
To find the frequency difference between successive modes we need to find frequency of second harmonic first
f₁ = (2/2l)*(sqr.root(T/μ))
f₁ = (2/2(347))*
f₁ = 12.71 Hz
Difference is:
Δf = f₁ - f₀ = 12.71 - 6.355
= 6.35 Hz
Answer:
Explanation:
The magnetic field B inside long solenoid with current I is given as
where
N is number of turn of solenoids = 1140 turns
I is current that passes through solenoid
L is length along which current pass = 0.350 m
plugging value to get required value of current
Answer:(a)9.685 mm
(b)4.184 mm
Explanation:
Given
Wavelength of light
Width of slit(b)=0.210
(a)Width of central maximum located 1.80m from slit
=9.685 mm
(b)Width of the first order bright fringe
Well Hmm how much you tell me it’s your work lol