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Crank
3 years ago
8

Which other element is most likely to be a nonreactive gas?

Chemistry
2 answers:
iragen [17]3 years ago
8 0

Option [D] Krypton, Kr number 36

icang [17]3 years ago
4 0

Answer:

Choice D. Among the choices, \rm Kr (krypton) is likely to be the most similar to neon and behave as a non-reactive gas.

Explanation:

Columns in the periodic table are called "groups." Elements in the same group (i.e., same column of the periodic table) tend to have similar chemical properties.

In this example, neon is in the same right-most column of the periodic table. Since neon is a non-reactive gas, it is reasonable to infer that other elements in the same column would behave similarly.

Among the choices, krypton ({\rm Kr}) is the only element in the same column. Thus, krypton would be the most likely element to be a nonreactive gas.

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Alex17521 [72]

Answer:

The physical and chemical properties of the product do not match the properties of the reactant.

Explanation:

Chemical change:

The changes, that occur due to change in the composition of a substance and result in a different compound is known as chemical change.

These changes are irreversible

These changes occur due to chemical reactions

These may not be observed with naked eye

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6 0
3 years ago
Noble Gases (18): (Name all noble gases)
Paul [167]

Answer :

  • The Noble gasses are Helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), Radon (Rn).
  • When air is cold, Oxygen liquefies first at -182^oC. N_2 liquefies at -195^oC. About 1% of the air is still gas composed of the noble gas Argon, Ar.
  • One noble gas was discovered on the sun. It’s spectrum was identify first. This is Helium, He.
  • One of noble gas is radioactive and seeps up your basement floors and walls. It is Radon, Rn.
  • This noble gas is used in electronic flashes and other bright lights. It is Xenon, Xe.
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3 0
4 years ago
A particular first-order reaction has a rate constant of 1.35 × 102 s-1 at 25.0°C. What is the magnitude of k at 95.0°C if Ea =
never [62]

Answer:

k ≈ 9,56x10³ s⁻¹

Explanation:

It is possible to solve this question using Arrhenius formula:

ln\frac{k2}{k1} = \frac{-Ea}{R} (\frac{1}{T2} -\frac{1}{T1} )

Where:

k1: 1,35x10² s⁻¹

T1: 25,0°C + 273,15 = 298,15K

Ea = 55,5 kJ/mol

R = 8,314472x10⁻³ kJ/molK

k2 : ???

T2: 95,0°C+ 273,15K = 368,15K

Solving:

ln\frac{k2}{k1} = 4,257

\frac{k2}{k1} = 70,593

{k2} = 9,53x10^3 s^{-1}

<em>k ≈ 9,56x10³ s⁻¹</em>

I hope it helps!

5 0
3 years ago
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