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ankoles [38]
3 years ago
9

can you guys please help me answer this, I have an assignment and I have to submit it in 5 minutes, please help

Chemistry
1 answer:
Alborosie3 years ago
7 0

Answer:

c

Explanation:

kinetic energy can be calculated using the formula

=1/2*mass*velocity or speed ^2

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Give the name of this alcohol.
solong [7]

Answer:

An alcohol is an organic compound with a hydroxyl (OH) functional group on an aliphatic carbon atom. Because OH is the functional group of all alcohols, we often represent alcohols by the general formula ROH, where R is an alkyl group. Alcohols are common in nature.

Explanation:

3 0
2 years ago
What part of the geocentric model was incorporated in the heliocentric model?
boyakko [2]
C. A central body is the center of the universe.
4 0
3 years ago
Consider the formation of [Ni(en)3]2+ from [Ni(H2O)6]2+. The stepwise ΔG∘ values at 298 K are ΔG∘1 for first step=−42.9 kJ⋅mol−1
timurjin [86]

Answer:

kf = 1.16 x 10¹⁸

Explanation:

Step 1: [Ni(H₂O)₆]²⁺  + 1en → [Ni(H₂O)₄(en)]²⁺  ΔG°1 = -42.9 kJmol⁻¹

Step 2: [Ni(H₂O)₄(en)]²⁺  + 1en → [Ni(H₂O)₂(en)₂]²⁺  ΔG°2 = -35.8 kJmol⁻¹

Step 3: [Ni(H₂O)₂(en)₂]²⁺ + 1en →  [Ni(en)₃]²⁺  ΔG°3 = -24.3 kJmol⁻¹

________________________________________________________

Overall reaction: [Ni(H₂O)₆]²⁺  + 3en → [Ni(en)₃]²⁺  ΔG°r

ΔG°r = ΔG°1 + ΔG°2 + ΔG°3

ΔG°r = -42.9 - 35.8 - 24.3

ΔG°r = -103.0 kJmol⁻¹

ΔG°r = -RTlnKf

-103,000 Jmol⁻¹ =  - 8.31 J.K⁻¹mol⁻¹ x 298 K x lnKf

kf = e ^(-103,000/-8.31x298)

kf = e ^41.59

kf = 1.16 x 10¹⁸

7 0
3 years ago
Write the Ka expression for an aqueous solution of hydrofluoric acid: (Note that either the numerator or denominator may contain
damaskus [11]

Answer:

Ka = ( [H₃O⁺] . [F⁻] ) / [HF]

Explanation:

HF is a weak acid which in water, keeps this equilibrium

HF (aq)  +  H₂O (l)  ⇄  H₃O⁺ (aq)  +  F⁻ (aq)      Ka

2H₂O (l)  ⇄  H₃O⁺ (l)  +  OH⁻ (aq)   Kw

HF is the weak acid

F⁻ is the conjugate stron base

Let's make the expression for K

K = ( [H₃O⁺] . [F⁻] ) / [HF] . [H₂O]

K . [H₂O] = ( [H₃O⁺] . [F⁻] ) / [HF]

K . [H₂O] = Ka

Ka, the acid dissociation constant, includes Kwater.

4 0
3 years ago
atch the following aqueous solutions with the appropriate letter from the column on the right. fill in the blank 1 A 1. 0.20 m N
Firdavs [7]

Answer:

Highest boiling point - 0.43 m Urea

Second highest boiling point - 0.20 m NiSO4

Third highest boiling point - 0.19 m NH4I

Lowest boiling point - 0.17 m NH4NO3

Explanation:

We know that;

ΔT = kb m i

Where;

ΔT = boiling point elevation

kb = boiling point constant

m = molality of the solution

i = Van't Hoff factor

For NiSO4 , NH4I  and NH4NO3 , the Van't Hoff factor, i = 2

But for Urea, the Van't Hoff factor, i = 1

We also have to consider both the values of the molality and Van't Hoff factor , knowing that a higher molality and a higher Van't Hoff factor leads to a higher ΔT and consequently a higher boiling point.

This facts above account for the arrangement of substances shown in the answer.

6 0
3 years ago
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