Answer:
The person solving the problem first subtracted 6 from 15. Since the cube root is next to the six, the problem should be read as ![15-6(\sqrt[3]{\frac{-1000}{27} } )](https://tex.z-dn.net/?f=15-6%28%5Csqrt%5B3%5D%7B%5Cfrac%7B-1000%7D%7B27%7D%20%7D%20%29)
rather than ![(15-6)(\sqrt[3]{\frac{-1000}{27} } )](https://tex.z-dn.net/?f=%2815-6%29%28%5Csqrt%5B3%5D%7B%5Cfrac%7B-1000%7D%7B27%7D%20%7D%20%29)
.
- To solve it correctly, first find the cube root of -1000/27: <u>-10/3</u>
- Next, multiply by 6: -20
- Finally, subtract from 15: 35
please lmk if anything is wrong with my answer, hope this helps :)
First find a parameterization for the curve of intersection.
Given the equation of a cylinder, a natural choice for a parameterization would be one utilizing cylindrical coordinates. Here,
which suggests we could use
with 
, and we get 
from the equation of the plane,
Now use the arc length formula:
Answer:
2(d-vt)=-at^2
a=2(d-vt)/t^2
at^2=2(d-vt)
Step-by-step explanation:
Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula, d is
displacement, v is final velocity, a is acceleration, and t is time.
Given the formula for calculating the displacement of a body as shown below;
d=vt - 1/2at^2
Where,
d = displacement
v = final velocity
a = acceleration
t = time
To make acceleration(a), the subject of the formula
Subtract vt from both sides of the equation
d=vt - 1/2at^2
d - vt=vt - vt - 1/2at^2
d - vt= -1/2at^2
2(d - vt) = -at^2
Divide both sides by t^2
2(d - vt) / t^2 = -at^2 / t^2
2(d - vt) / t^2 = -a
a= -2(d - vt) / t^2
a=2(vt - d) / t^2
2(vt-d)=at^2
The answer is A=81. You multiply 9 x 9 and then you get 81. Since all sides on a square are equal, you multiply the side length by itself to get the area. Hope that helps! Have a great day!
