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3 years ago

What are the primary atoms that make up the scents that we smell?

Chemistry

2 answers:

iren2701 [21]3 years ago

7 0

Answer and Explanation:

These are really gas atoms which diffuse with air and spread aroma.

Aromatic compounds , otherwise called arenes or aromatics, are synthetic exacerbates that contain conjugated planar ring frameworks with delocalized pi electron mists rather than discrete exchanging single and double bonds.

Natural mixes with C and H can smell lovely. Compounds with nice aromas have no direct link with scent, although many are known pleasant aromas.

Esters have pleasant smelling compounds and some of the foul smell arises as a result of the presence of sulphur or hydrogen groups.

Scorpion4ik [409]3 years ago

3 0

Answer:

Molecules make scents. Aromatic ones (That is, containing rings of carbon atoms with delocalised electrons). Some unpleasant smells are due to hydrogen and sulphur groups.

Explanation:

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As temperature increases, the amount of solute that a solvent can dissolve increases. True False

ra1l [238]

<span>As temperature increases, the amount of solute that a solvent can dissolve increases.</span>

<span>Answer: False
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6 0

3 years ago

Acid rain can be destructive to both the natural environment and human-made structures. The equation below shows a

guapka [62]

Answer:

Explanation:

What the equation is tell you is that for every 3 mols of NO2 you get 2 mol of HNO3

3 mol NO2 / 2 mol HNO2 ===> 300.00 mol NO2 / x Cross multiply

3x = 2 * 300

3x = 600 Divide by 3

3x/3 = 600/3 Do the division

x = 200.00

3 0

3 years ago

What is the number of protons in this carbon atom?

motikmotik

A - 12

The amount of protons in a specific element do not change, for if the protons change, then the element themselves change. Therefore, no matter what, if the question specifies the element (i.e. Carbon) then the amount of protons will remain the same as seen on the periodic table.

Hope this helps!

8 0

3 years ago

What is the temperature (°c) of 2.48 moles of gas stored in a 30.0 l container at 1559 mm hg? (r= 0.0821 l atm/ mol k)?

Lemur [1.5K]

Answer is: the temperature is 28.9°C.

n = 2.48; amount of the gas.

V = 30.0 L; volume of the gas.

p = 1559 mmHg ÷ 760 mmHg/atm.

p = 2.05 atm; pressure of the gas.

R = 0.0821 L·atm/mol·K.

Ideal gas law: p·V = n·R·T.

T = p·V ÷ (n·R).

T = 302.05 K - 273.15.

T = 28.9°C; temperature of the gas.

3 0

3 years ago

Draw the Lewis structure for SO32−, including lone pairs. Select Draw Rings More Erase Select Draw Rings More Erase Select Draw

balandron [24]

Answer : The molecular shape of $SO_3^{2-}$ is trigonal pyramidal and bond angle between O-S-O is

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, $SO_3^{2-}$

As we know that sulfur has '6' valence electrons and oxygen also has '6' valence electron.

Therefore, the total number of valence electrons in $SO_3^{2-}$ = 6 + 3(6) + 2 = 26

According to Lewis-dot structure, there are 8 number of bonding electrons and 18 number of non-bonding electrons or lone pair electrons.

The Lewis-dot structure of $SO_3^{2-}$ is shown below.

Formula used :

$\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

Now we have to determine the hybridization of the given molecule, $SO_3^{2-}$

$\text{Number of electrons}=\frac{1}{2}\times [6+2]=4$

The number of electron pair are 4 that means the hybridization will be $sp^3$ and the electronic geometry of the molecule will be tetrahedral.

But as there are 3 atoms around the central sulfur atom, the fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be trigonal pyramidal and the bond angle between O-S-O is less than $109.5^o$ due to repulsion between lone and bond pair of electrons.

5 0

4 years ago