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MaRussiya [10]
3 years ago
13

Please Help with this

Physics
1 answer:
mars1129 [50]3 years ago
3 0

Answer: option 3    Ta < Tb = Tc < Td

Explanation:

Ta = mv²/r                            =   mv²/r

Tb = m(2v)²/2r = (m)4v²/2r  = 2mv²/r

Tc = (2m)v²/r                        = 2mv²/r

Td = (2m)(2v)²/r = (2m)4v²/r = 8mv²/r

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A 0.200-m uniform bar has a mass of 0.795 kg and is released from rest in the vertical position, as the drawing indicates. The s
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Explanation:

Since, the rod is present in vertical position and the spring is unrestrained.

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       mass of the bar = 0.795 kg

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Also,    \omega = \frac{\nu}{L}

where,    \nu = speed of the tip of the rod

              x = spring extension

The initial unstrained length is x_{o} = 0.1 m

Therefore, final length will be calculated as follows.

              x' = \sqrt{(0.2)^{2} + (0.1)^{2}} m

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       \frac{mgL}{2} = \frac{1}{2}kx^{2} + \frac{1 \times mL^{2}}{2 \times 3}(\frac{\nu}{L})^{2}

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Putting the given values into the above formula as follows.

   \frac{mgL}{2} = \frac{1}{2}kx^{2} + \frac{1}{6}mv^{2}

  \frac{0.795 kg \times 9.8 \times 0.2 m}{2} = \frac{1}{2} \times 27 N/m \times (0.1236)^{2} + \frac{1}{6} \times 0.795 \times v^{2}

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