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3 years ago

PLEASE HELP WHAT IS THE RIGHT ANSWER

Chemistry

1 answer:

AveGali [126]3 years ago

5 0

Answer:

Explanation:

Weak acids dissociate only slightly in an aqueous solution. The majority of molecules remain undissociated.

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What are the two models of arrangement for the first periodic table?

LUCKY_DIMON [66]

Answer:

the modals of arrangement for first periodic table was. increasing atomic mass and grouping together of elements having similar properties

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3 years ago

Why are organic compounds predominantly covalent?

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because all organic compounds have in common the presence of carbon atoms and hydrogen atoms.

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3 years ago

What is the key difference between element and compound

olga nikolaevna [1]

Answer and Explanation:

DIFFERENCE BETWEEN ELEMENT AND COMPOUND :

An element is made up of same type of atoms whereas a compound is made up of different type of atoms.
A compound can be separated by chemical methods but an element can not be separated by chemical methods.
Example of element is Cu Fe C and example of compound is $CO_2\ NO_2 \ NH_3$ etc
Elements can not be split into different substances but compound can be splited into different substances

3 0

3 years ago

Calculate the [H+] and pH of a 0.0040 M hydrazoic acid solution. Keep in mind that the Ka of hydrazoic acid is 2.20×10−5. Use th

Vera_Pavlovna [14]

Answer:

$[H^+]=0.000285$

$pH=3.55$

Explanation:

In this, we can with the ionization equation for the hydrazoic acid ( $HN_3$ ). So:

$HN_3~~H^+~+~N_3^-$

Now, due to the Ka constant value, we have to use the whole equilibrium because this is not a strong acid. So, we have to write the Ka expression:

$Ka=\frac{[H^+][N_3^-]}{[HN_3]}$

For each mol of $H^+$ produced we will have 1 mol of $N_3^-$ . So, we can use "X" for the unknown values and replace in the Ka equation:

$Ka=\frac{X*X}{[HN_3]}$

Additionally, we have to keep in mind that $HN_3$ is a reagent, this means that we will be consumed. We dont know how much acid would be consumed but we can express a subtraction from the initial value, so:

$Ka=\frac{X*X}{0.004-X}$

Finally, we can put the ka value and solve for "X":

$2.2X10^-^5=\frac{X*X}{0.004-X}$

$2.2X10^-^5=\frac{X^2}{0.004-X}$

$X= 0.000285$

So, we have a concentration of 0.000285 for $H^+$ . With this in mind, we can calculate the pH value:

$pH=-Log[H^+]=-Log[0.000285]=3.55$

I hope it helps!

8 0

3 years ago

It is found that 250 ml of gas at stp has a mass of .675 g what is the molar mass

katrin2010 [14]

Answer:

61.3 g/mol

Step-by-step explanation:

We can use the Ideal Gas Law to solve this problem:

pV = nRT

Since n = m/M, the equation becomes

pV = (m/M)RT Multiply each side by M

pVM = RT Divide each side by RT

M = (mRT)/(pV)

Data:

m = 0.675 g

R = 0.0.083 14 bar·L·K⁻¹mol⁻¹

T = 0 °C = 273.15 K

p = 1 bar

V = 250 mL = 0.250 L

Calculation: 

M= (0.675 × 0.083 14 × 273.15)/(1 × 0.250)

M= 15.33/0.250

M= 61.3 g/mol

4 0

3 years ago