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aleksley [76]
3 years ago
9

Please help Convert the following distance v time graph velocity graph

Physics
1 answer:
Reil [10]3 years ago
5 0

Explanation:

for v vs t graph for t=9 to 11,v=15kmph

similarly v2=0,v3=60kmph&v4= -40kmph

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What is the name of the force that acts between any two objects because of<br>their masses?​
svetoff [14.1K]

Answer:

Explanation:

The force of attraction between 2 masses.

4 0
3 years ago
9. A 5.0 kg block on an inclined plane is acted upon by a horizontal force of 100 N shown in the figure below. The coefficient o
Helga [31]

Answer:

A: The acceleration is 7.7 m/s up the inclined plane.

B: It will take the block 0.36 seconds to move 0.5 meters up along the inclined plane

Explanation:

Let us work with variables and set

m=5kg\\\\F_H=100N\\\\\mu=0.3\\\\\theta=37^o.

As shown in the attached free body diagram, we choose our coordinates such that the x-axis is parallel to the inclined plane and the y-axis is perpendicular. We do this because it greatly simplifies our calculations.

Part A:

From the free body diagram we see that the total force along the x-axis is:

F_{tot}=mg*sin(\theta)+F_s-F_Hcos(\theta).

Now the force of friction is F_s=\mu*N, where N is the normal force and from the diagram it is F_y=mg*cos(\theta).

Thus F_s=\mu*N=\mu*mg*cos(\theta).

Therefore,

F_{tot}=mg*sin(\theta)+\mu*mg*cos(\theta)-F_Hcos(\theta)\\\\=mg(sin(\theta)+\mu*cos(\theta))-F_Hcos(\theta).

Substituting the value for F_H,m,\mu, and \:\theta we get:

F_{tot}= -38.63N.

Now acceleration is simply

a=\frac{F_H}{m} =\frac{-38.63N}{5kg} =-7.7m/s.

The negative sign indicates that the acceleration is directed up the incline.

Part B:

d=\frac{1}{2} at^2

Which can be rearranged to solve for t:

t=\sqrt{\frac{2d}{a} }

Substitute the value of d=0.50m and a=7.7m/s and we get:

t=0.36s.

which is our answer.

Notice that in using the formula to calculate time we used the positive value of a, because for this formula absolute value is needed.

5 0
3 years ago
How would i solve for force when there are multiple accelerations?
damaskus [11]

"Multiple accelerations" is a puzzling phrase, and I'd be curious to understand it
better.  Sadly however, you haven't explained it at all.

If the multiple accelerations are the accelerations of multiple objects, then
the net force on each object is the product of (its mass) x (its acceleration).

If the multiple accelerations are the acceleration of one object at different times,
then at any instant of time, the net force on the object is the product of (its mass) x
(its acceleration at that instant).

8 0
3 years ago
Example of electrical to mechanical​
Sonja [21]

Answer:

dynamo generator could be the right ans

6 0
3 years ago
Read 2 more answers
J. Ram travels 50 m on a straight road in 30 s. Hari covers the same distance
ira [324]

Explanation:

Explanation:

In the given question, there are two conditions.

Ram traveled 50 m in 30 seconds in a straight road.

Hari covers the same distance in the road; that means 50 m in 45 seconds

The formula for work w=\frac{d}{t}w=td

Ram's work w=\frac{50}{30}=1.66666w=3050=1.66666

Hari's work w=\frac{50}{45}=1.111w=4550=1.111

Ram is slower than Hari and the velocity of Ram is slower than Hari.

Ram has done less work than Hari.

Hence, Hari has done more work and he has more power than Ram.

6 0
2 years ago
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