<span>If you have only two
data from two recording stations then you will be having a hard time finding
the correct location of the epicenter. This is because triangulation method requires
3 recording station. If you have 2 recording station, the 2 circles will
intersect at 2 points giving you 2 locations that could possibly be the
epicenter.</span>
A current carrying wire placed perpendicular to a magnetic field experiences a force equal to
where
I is the current in the wire
L is the wire length
B is the intensity of the magnetic field
In our problem, the length of the wire is L=1.0 m, the magnetic field strength is B=0.20 T and the force exerted on the wire is F=0.60 N. If we re-arrange the equation and we plug these numbers into it, we find the current in the wire:
Explanation:
10
/9 Ω
potential difference across the cell in open circuit is the emf of the cell.
Hence, emf E=2.2V
when, circuit is closed, potential difference across cell is given by V=E−Ir
And,
I= E/
R+r
Hence, V= E− Er/
R+r
⟹ V= ER/
R+r
⟹ 1.8= 2.2×5
/5+r
⟹9+1.8r=11
⟹ r= 2/ 1.8 Ω
⟹ r= 10/9 Ω
Answer:
The answer is below
Explanation:
a) The volume of a sphere is:
Volume = (4/3)πr³; where r is the radius of the shell.
Given the outside radius of 2.60 cm and inner radius of a cm, the volume of the spherical shell is:
Volume of spherical shell = cm³
But Density = mass / volume; Mass = density * volume.
Therefore, mass of spherical shell = density * volume
mass of spherical shell = * cm³
Mass of liquid = volume of inner shell * density of liquid
Mass of liquid =
Total mass of sphere including contents = mass of spherical shell + mass of liquid
Total mass of sphere including contents (M) = * + =
Total mass of sphere including contents (M) = (346 - 14.5a³) grams
b) The mass is maximum when the value of a = 0
M = 346 - 14.5a³
M' = 43.5a² = 0
43.5a² = 0
a = 0