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3 years ago

A 1.0 kg object is attached to a 0.50 m string. It is twirled in a horizontal circle above the ground at a speed of 5.0 m/s.

Physics

1 answer:

7nadin3 [17]3 years ago

4 0

Given that,

Mass of the object, m = 1 kg

It moves in a circle of radius 0.5 m with a speed of 5 m/s

To find,

The direction of the acceleration.

Solution,

Whenever an object moves in a circular path, the only force that acts on its is centripetal force which is given by the formula as follows :

$F=\dfrac{mv^2}{r}$

The centripetal acceleration acts in the direction of force. It acts along the radius of the circular path. In this figure, the direction of the acceleration is shown at point d.

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The dimensions of aluminum foil in a box for sale in super markets are 66 2/3 yards by 12 inches. the mass of the foil is 0.83 k

disa [49]

Length of the sheet is given as

$L = \frac{200}{3} yards = 6096 cm$

width of the sheet is given as

$w = 12 inches = 30.48 cm$

now let say its thickness is "t"

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$V = L*w*t$

$V = 6096*30.48* t$

$V = 185806.08*t cm^3$

mass of the sheet is given as

$m = 0.83 kg = 830 gram$

now we have

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$2.70 = \frac{830}{185806.08*t}$

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3 years ago

.2, A car starting from rest has an acceleration of

riadik2000 [5.3K]

Answer: 2.5 m/s and 6.25 m

Explanation:

u = 0

a = 0.5 m/s²

t = 5 s

v = u + at

= 0 + 0.5 × 5

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s = ut + 1/2 at²

= 1/2 × 2.5 × 5

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7 0

4 years ago

A marble is dropped off the top of a building. Find it's velocity and how far below to its dropping point for the first 10 secon

Yuri [45]

consider the motion in y-direction

v₀ = initial velocity = 0 m/s

a = acceleration = g = - 9.8 m/s²

t = time

v = final velocity at any time "t"

velocity at any time is given as

v = v₀ + at

v = 0 + (- 9.8) t

v = (- 9.8) t

so at t = 1 , v = (- 9.8) (1) = - 9.8 m/s

at t = 2 , v = (- 9.8) (2) = - 19.6 m/s

at t = 3 , v = (- 9.8) (3) = - 29.4 m/s and so on

Y₀ = initial position where the marble was dropped from = 0 m

Y = final position at any time "t"

final position at any time "t" is given as

Y = Y₀ + v₀ t + (0.5) a t²

Y = 0 + (0) t + (0.5) (-9.8) t²

Y = - 4.9 t²

at t = 1 , Y = - 4.9 (1)² = - 4.9 m

at t = 2 , Y = - 4.9 (2)² = - 19.6 m

at t = 3 , Y = - 4.9 (3)² = - 44.1 m

and So on

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3 years ago

Which are true for a photon. (Choose 3)

ser-zykov [4K]

A c and e are correct but b and d are incorrect. i hope this helped

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Which of the following is a scalar quantity?

aalyn [17]

A. 14 gallons.

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3 years ago