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skad [1K]
3 years ago
6

Plz help!!!

Physics
1 answer:
shtirl [24]3 years ago
3 0

Answer:

I think the answer to your question is true

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A 10 ohms resistor is powered by a 5-V battery. The current flowing<br> through the source is:
mario62 [17]
  • Resistance=R=10ohm
  • Voltage=V=5V
  • Current=I

Applying ohm's law

\\ \sf\longmapsto \dfrac{V}{I}=R

\\ \sf\longmapsto I=\dfrac{V}{R}

\\ \sf\longmapsto I=\dfrac{5}{10}

\\ \sf\longmapsto I=0.5A

4 0
2 years ago
Summerize how friction and inertia act on an object sliding on a flat surface
natta225 [31]
Inertia is when a object in motion will stay in motion or in a standing still state unless acted upon by a unbalancing force.
Friction is when a object slows down because it is rubbing against another object.

If a object is sliding across a surface, theoretically, it would not stop but because it is on a flat surface it would experience friction, this will disperse some of the kinetic energy that it has thus slowing the object down eventually, after some time, to a stop.

Hope this helps! :)
5 0
3 years ago
Marcus drove his Honda Prelude for 4 hours at a rate of 55 miles per hour. How far did he travel?
galben [10]
To solve this, you’d multiply 55 by 4, because he is travelling 55 miles every hour, for four hours, which means 55 miles every hour. The answer would be 220.
7 0
3 years ago
Read 2 more answers
A 40.0 kg box is placed on a 2.00 m tall shelf. If the box falls off the shelf, what is its kinetic energy as it strikes the gro
RUDIKE [14]
M = 40 Kg , g=9.8 m/s² , h = 2 m

PE = m g h

PE = (40) (9.8) (2)

PE = 784 J

KE = PE

½m v² = m g h

½ v² = g h

½ v² = (9.8) (2)

½ v² = 19.6

v² = 19.6×2

v² = 39.2

V = √39.2

V = 6.26 m/s

KE = ½mv²

KE = ½(40) (6.26)²

KE =783.8 J
6 0
2 years ago
A truck speeds up from velocity of 6m/s to 14m/s in 4 seconds. what is the trucks acceleration?
Tanzania [10]

To calculate the acceleration of the truck, we use the equation of motion

v = u + at

Here, v is final velocity of the truck, u is initial velocity of truck, a is acceleration of the truck and t is time taken.

Given,  u = 6 m/s, v = 14 m/s and t = 4 s.

Substituting these values in above equation, we get

14 \ m/s = 6 \ m/s + a \times 4 \ s \\\\  a = \frac{14 \ m/s - 6 \ m/s}{ 4 \ s } =  2 \ m /s^2.

Thus,  the truck acceleration is 2 \ m /s^2

3 0
3 years ago
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