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BartSMP [9]
3 years ago
15

A fine-grained soil has a liquid limit of 200%, determined from the Casagrande cup method. The plastic limit was measured by rol

ling threads of soil to be 45%. The water content of the soil is determined to be 60% in the field by oven-drying a field sample. The clay content is 63%, determined via sieve and hydrometer testing and the plasticity chart. Determine: (a) Plasticity index, liquidity index, and the activity. (b) What state is the clay (liquid, plastic, semi-solid, etc.) and why
Engineering
1 answer:
Minchanka [31]3 years ago
6 0

Answer:

a)

Plasticity index I_P  = 155%

Liquidity index I_L = 0.09677

Activity A = 2.4603

b)

Consistency index of the clay = 0.9032

Since Liquidity index of soil( 0.09677) is between 0 and 0.25 and Consistency index (0.9032 ) is between 0.75 and 1; Then, The Clay is in Plastic State

Explanation:

Given that;

Liquid Limit W_{L} = 200%

Plastic Limit W_{P} = 45%

Natural Water Content W_N = 60%

Clay Content C_C = 63%;

(a) Plasticity index, liquidity index, and the activity.

Plasticity index I_P = Liquid Limit W_{L} - Plastic Limit W_{P}

Plasticity index I_P = 200% - 45%

Plasticity index I_P  = 155%

Liquidity index I_L = [ (Natural Water Content W_N - Plastic Limit W_{P} = 45%) /  Plasticity index I_P]

so;

Liquidity index I_L = ( 60 - 45)/155

Liquidity index I_L = 15 / 155

Liquidity index I_L = 0.09677

the activity A is;

A = Plasticity index I_P  / Clay Content C_C

Activity A = 155 / 63

Activity A = 2.4603

b) What state is the clay;

To get the state in which is in, we use the consistency index of Soil. which is given as follows;

I_C = [( Liquid Limit W_{L} - Natural Water Content W_N ) / Plasticity index I_P]

we substitute

I_C  = ( 200 - 60) / 155

I_C  = 140 / 155

I_C  = 0.9032

Consistency index of the clay = 0.9032

Since Liquidity index of soil( 0.09677) is between 0 and 0.25 and Consistency index (0.9032 ) is between 0.75 and 1; Then, The Clay is in Plastic State

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