To find the answer, take 55 and divide it by 1.85 to get the thickness of one card. In this case the answer would be 29.72973 cm. each.
Explanation:
Formula to represent thrust is as follows.
F = 
= 
or, p = 
F = 
= 
= 201.67 N
Thus, we can conclude that the thrust is 201.67 N.
Explanation:
Solution:
Let the time be
t1=35min = 0.58min
t2=10min=0.166min
t3=45min= 0.75min
t4=35min= 0.58min
let the velocities be
v1=100km/h
v2=55km/h
v3=35km/h
a. Determine the average speed for the trip. km/h
first we have to solve for the distance
S=s1+s2+s3
S= v1t1+v2t2+v3t3
S= 100*0.58+55*0.166+35*0.75
S=58+9.13+26.25
S=93.38km
V=S/t1+t2+t3+t4
V=93.38/0.58+0.166+0.75+0.58
V=93.38/2.076
V=44.98km/h
b. the distance is 93.38km
Acceleration of the table: B. 0.50 meters/second2
Explanation:
The problem can be solved by using Newton's second law of motion, which states that the net force acting on an object is the product of its mass and its acceleration. Mathematically:
where
is the net force
m is the mass
a is the acceleration
For the table in this problem, we have:
is the net force on the table, because there are two forces of 125 N and 120 N acting in opposite directions
m = 10.0 kg is the mass of the table
Solving for a, we find the acceleration:
Learn more about Newton's second law:
brainly.com/question/3820012
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Answer:
Explanation:
According to Newton's law of gravitation , all objects should take same time to fall from same height , but it does not happen when we see a paper , a thermocol and a plastic paper to fall .
It happens due to air resistance . In case of paper , this is most pronounced , so it falls slowest . In case of plastic paper , the resistance is least so it falls fastest .
If we squeeze the piece of paper to make a lump so that it does not remain flat , it will fall the fastest , because in this case the air resistance on it becomes the least .
