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SVETLANKA909090 [29]
3 years ago
13

What is the correct equation for the solubility product when calcium phosphate is dissolved in water

Chemistry
1 answer:
AlladinOne [14]3 years ago
7 0

Answer:

The solubility of calcium phosphate is

2.21x10−4g/L.

Explanation:

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calculate δg o for each reaction using δg o f values: (a) h2(g) i2(s) → 2hi(g) 2.6 kj (b) mno2(s) 2co(g) → mn(s) 2co2(g) kj (c)
Reika [66]

(a)The change in Gibbs free energy for the reaction has been 2.6 kJ/mol.

(b) The change in Gibbs free energy for the reaction has been -49.3 kJ/mol.

(c) The change in Gibbs free energy for the reaction has been 91.38 kJ/mol.

6 0
2 years ago
You have dissolved 10 g sodium oxide in 200 ml water.calculate. the concentration of the solution​
mash [69]

0.05M is the concentration of the solution​.

The amount of a chemical substance in a mixture is expressed by the substance's concentration. Concentration can be expressed in numerous ways. In chemistry, the terms "solvent" and "solute" are used to denote the substance of interest and the medium in which it is dissolved, respectively

Subtract the solute's mass from the total volume of the solution. Using m as the solute's mass and V as the total volume of the solution, write out the equation C = m/V. To get the concentration of your solution, divide the mass and volume figures you discovered and plug them in.

C = m / V

C = 10 / 200

C = 0.05M.

Learn more about concentration here:

brainly.com/question/10725862

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6 0
2 years ago
Calculate the unknown quantity in each of the following measurements of gases ?
hjlf

You have to google the answers

5 0
4 years ago
What type of reaction is shown by this equation?
Romashka-Z-Leto [24]
This is an acid base reaction which is basically a double displacement reaction. However, since carbonic acid is produced, it rapidly decomposes to carbon dioxide and water.
5 0
3 years ago
Calculate by (a)% weight and (b) %mole each of the elements present in sugar
Musya8 [376]

Explanation:

Molecular mass of sugar = C_{12}H_{22}O_{11} : = 432 g/mol

Atomic mass of carbon atom = 12 g/mol

Atomic mass of hydrogen atom = 1 g/mol

Atomic mass of oxygen atom = 16 g/mol

a) Percentage of an element in a compound:

\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of compound}}\times 100

Percentage of carbon by weight in C_{12}H_{22}O_{11}:

\frac{12\times 12 g/mol}{342 g/mol}\times 100=42.10\%

Percentage of hydrogen by weight in C_{12}H_{22}O_{11}:

\frac{22\times 1g/mol}{342 g/mol}\times 100=6.43\%

Percentage of oxygen by weight in C_{12}H_{22}O_{11}:

\frac{11\times 16g/mol}{342 g/mol}\times 100=51.46\%

b) Percentage of mole each of the elements present in sugar:

=\frac{\text{Moles of atoms of an element}}{\text{total moles of all types of atoms}}\times 100

In mole of sugar we have 12 moles of carbon atom , 22 moles of hydrogen atoms and 11 moles of oxygen atoms.

Percentage of carbon by mole in C_{12}H_{22}O_{11}:

\frac{12 mol}{45 mol}\times 100=26.66\%

Percentage of hydrogen by mole in C_{12}H_{22}O_{11}:

\frac{22 mol}{45 mol}\times 100=48.88\%

Percentage of oxygen by mole in C_{12}H_{22}O_{11}:

\frac{11 mol}{45 mol}\times 100=24.44\%

7 0
4 years ago
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