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Pepsi [2]
3 years ago
8

:( Write out the equation for combustion of solid calcium and balance the equation

Chemistry
2 answers:
Gennadij [26K]3 years ago
6 0
Use Socratic for the answer hope it hlo elf
topjm [15]3 years ago
4 0
Umm i need Brainlyest bad right now so if you are very kind you will help me
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1 A 3.80 g sample of bronze was dissolved in sulphuric acid. The copper in alloy reacted with
s344n2d4d5 [400]

Answer:

yeyeye

Explanation:

hi and bye  no problem you will come and die

3 0
3 years ago
`You have to be careful about pouring drano down your pipes since it is mainly hydrochloric acid--you can't do it if they are ma
Zanzabum

Answer:

6.67 moles

Explanation:

Given that:-

Moles of hydrogen gas produced = 10.0 moles

According the reaction shown below:-

2Al + 6HCl\rightarrow 2AlCl_3 +3H_2

3 moles of hydrogen gas are produced when 2 moles of aluminium undergoes reaction.

Also,

1 mole of hydrogen gas are produced when \frac{2}{3} moles of aluminium undergoes reaction.

So,

10.0 moles of hydrogen gas are produced when \frac{2}{3}\times 10.0 moles of aluminium undergoes reaction.

<u>Moles of Al needed  = \frac{2}{3}\times 10.0 moles = 6.67 moles</u>

6 0
3 years ago
6. A student is using colored beads to make a model of aluminum sulfate, Al2(SO4)3. Aluminum atoms are represented by blue beads
avanturin [10]

Answer:

H. 2 blue, 3 yellow, and 12 green

Explanation:

Aluminium atoms (Al) = Blue Beads

Oxygen Atoms (O) = Green Beads

Sulfur (S) = Yellow beads

From the compound Al2(SO4)3, the number of atoms present are;

Al = 2

S = 3

O = 12

This means the model would contain;

2 Blue beads

12 Green beads

3 Yellow beads

The correct option is; H. 2 blue, 3 yellow, and 12 green

7 0
3 years ago
QUESTION 4<br> Balance this chemical equation. A H2S + B Ag ---&gt; C Ag2S + DH2
photoshop1234 [79]

Answer:

1H2S + 2Ag --> 1Ag2S + 1H2

Explanation:

1H2S + 2Ag --> 1Ag2S + 1H2

You only have to make sure to have the same amount of each element in each side of your chemical equation

7 0
2 years ago
9.69×10^25 formula units of iron(III) nitrate is equal to how many moles of Fe(NO3)3?
scoray [572]

Answer:

160.9 mol ≅ 161.0 mol.

Explanation:

  • It is known that every 1.0 mole of compound or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms (formula units).

Using cross multiplication:

1.0 mole of Fe(NO₃)₃ contains → 6.022 x 10²³ formula units.

??? mole of Fe(NO₃)₃ contains → 9.69 x 10²⁵ formula units.

<em>∴ The no. of moles of He contains (9.69 x 10²⁵ formula units)</em> = (1.0 mol)(9.69 x 10²⁵ formula units.)/(6.022 x 10²³ formula units) = <em>160.9 mol ≅ 161.0 mol.</em>

6 0
3 years ago
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