Answer:
ωf = 13 rad/s
Explanation:
- The angular acceleration, by definition, is just the rate of change of the angular velocity with respect to time, as follows:
- α = Δω/Δt = (ωf-ω₀) / (tfi-t₀)
- Choosing t₀ = 0, and rearranging terms, we have

where ω₀ = 5 rad/s, t = 4 s, α = 2 rad/s2
- Replacing these values in (1) and solving for ωf, we get:

- The wheel's angular velocity after 4s is 13 rad/s.
Answer:
A
Explanation:
The slope of the graph has the units of vertical axis divided by horizontal axis. This means that the slope of a distance vs time graph is distance/time, or velocity.
Slope is calculated by "rise over run" so C is incorrect.
Since the slope represents velocity, a constant slope equates to a constant velocity, hence B is incorrect. Same reasoning for D being incorrect: if the slope is zero, the object is not moving.
A Tropical Rain Forest. It has both Biotic and Abiotic factors which will contribute to thousands of living things.
The magnitude and direction of the electric field in the wire are mathematically given as
![L &=[(v / L) v / m] \hat{i}](https://tex.z-dn.net/?f=L%20%26%3D%5B%28v%20%2F%20L%29%20v%20%2F%20m%5D%20%5Chat%7Bi%7D)
<h3>What is the magnitude and direction of the electric field in the wire?</h3>
Generally, the equation for is mathematically given as
A cylindrical wire that is straight and parallel to the x-axis has the following dimensions: length L, diameter d, resistivity p, diameter d, potential v, and z length. combining elements from both sides
E d 
![\begin{aligned}&-E \int_0^L d x=\int_v^0 d v \\\therefore E \cdot L &=v \\L &=[(v / L) v / m] \hat{i}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%26-E%20%5Cint_0%5EL%20d%20x%3D%5Cint_v%5E0%20d%20v%20%5C%5C%5Ctherefore%20E%20%5Ccdot%20L%20%26%3Dv%20%5C%5CL%20%26%3D%5B%28v%20%2F%20L%29%20v%20%2F%20m%5D%20%5Chat%7Bi%7D%5Cend%7Baligned%7D)
In conclusion, the magnitude and direction of the electric field in the wire are given as
![L &=[(v / L) v / m]](https://tex.z-dn.net/?f=L%20%26%3D%5B%28v%20%2F%20L%29%20v%20%2F%20m%5D)
Read more about electric fields
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