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VladimirAG [237]
3 years ago
11

Definition of continental polar

Physics
2 answers:
kipiarov [429]3 years ago
8 0

Answer:

Continental polar (cP) or continental arctic (cA) air masses are cold, dry, and stable. These air masses originate over northern Canada and Alaska as a result of radiational cooling. Maritime polar (mP) air masses are cool, moist, and unstable.

Explanation:

Dovator [93]3 years ago
6 0

cold, dry, and stable air masses .

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You kick a soccer ball with a mass of 2 kg. The ball leaves your foot with a speed of 30 m/s. How much kinetic energy does the b
Lyrx [107]

Answer:

KE= 900 (I think)

Explanation:

KE=½mv²

KE= ½(2)(30)²

KE=½(60)²

KE=30²

KE=900

Hope this helps!

7 0
2 years ago
Read 2 more answers
What is the displacement of the runner, whose velocity versus time graph is shown in the Figure, in the first 15.5 s?
muminat

Answer:

10 displacement of the runner

6 0
3 years ago
Two wheels having the same radius and mass rotate at the same angular velocity. One wheel is made with spokes so nearly all the
Mazyrski [523]

Answer:

C. The wheel with spokes has about twice the KE.

Explanation:

Given that

Mass , radius and the angular speed for both the wheels are same.

radius = r

Mass = m

Angular speed = ω

The angular kinetic energy KE given as

KE=\dfrac{1}{2}I\omega ^2

I=Moment of inertia for wheels

Wheel made of spokes

I₁ = m r²

Wheel like a disk

I₂ = 0.5 m r²

Now by comparing kinetic energy

\dfrac{KE_1}{KE_2}=\dfrac{I_1}{I_2}

\dfrac{KE_1}{KE_2}=\dfrac{mr^2}{0.5mr^2}

\dfrac{KE_1}{KE_2}=2

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Therefore answer is C.

5 0
3 years ago
What, roughly, is the percent uncertainty in the volume of a spherical beach ball whose radius is 5.66 0.09 m?
iren2701 [21]

Answer:

  • 4.77 %

Explanation:

We know that the volume V for a sphere of radius r is

V(r) = \frac{4}{3} \ \pi \ r^3

If we got an uncertainty \Delta r the formula for the uncertainty of V is:

\Delta V(r) = \sqrt{  (\frac{dV}{dr} \Delta r)^2  }

We can calculate this uncertainty, first we obtain the derivative:

\frac{dV}{dr}  = 3 * \frac{4}{3} \ \pi \ r^2

\frac{dV}{dr}  = 4 \ \pi \ r^2

And using it in the formula:

\Delta V(r) = \sqrt{  (4 \ \pi \ r^2\Delta r)^2  }

\Delta V(r) = \sqrt{  4^2 \ \pi^2 \ r^4 \Delta r^2  }

\Delta V(r) =  4 \  \pi \ r^2 \Delta r

The relative uncertainty is:

\frac{\Delta V(r)}{V(r)}

\frac{ 4 \  \pi \ r^2 \Delta r  }{ \frac{4}{3} \ \pi \ r^3}

\frac{ 3  \Delta r  }{  r}

Using the values for the problem:

\frac{ 3 * 0.09 m  }{  5.66 m} = 0.0477

This is, a percent uncertainty of 4.77 %

4 0
3 years ago
What is the SI unit for graviational potential energy
scZoUnD [109]

Gravitational potential energy is energy. 
The unit of energy is the Joule.

1 Joule = 1 kilogram-meter² / sec²


3 0
3 years ago
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