All categories

3 years ago

A 900 N student runs up the stairs 3.5 m high in 12 seconds. How much POWER do they generate?

Physics

1 answer:

never [62]3 years ago

4 0

Answer:

Ur litterly dog water ✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️

You might be interested in

What is an example of speed?

svlad2 [7]

<span>The speed is a scalar quantity which by definition is the distance traveled per unit of time. Unit for speed is: km/h. (how many km the object is moved for one hour) or mph (miles per hour).
From the given option D. A dog runs an average 8 mph. (this means that a dog is moving 8 miles per hour).

</span>

5 0

3 years ago

Un automóvil deportivo se mueve a rapidez constante viaja 110m en 5.0s si entonces frena y llega a detenerse en 4.0s ¿Cuál es su

noname [10]

Answer:

La aceleración del automovil antes de deternerse es -5.5 m/s².

Explanation:

Podemos encontar la aceleración del auto usando la siguiente ecuación:

$v_{f} = v_{0} + at$

En donde:

$v_{f}$ : es la velocidad final = 0 (se detiene)

$v_{f}$ : es la velocidad inicial

a: es la aceleración=?

t: es el tiempo = 4.0 s

Primero debemos encontrar la velocidad inicial, para ellos usaremos la siguiente ecuación de moviemiento rectilíneo uniforme:

$v_{0} = \frac{x}{t} = \frac{110 m}{5.0 s} = 22 m/s$

Ahora, la aceleración es:

$a = \frac{v_{f} - v_{0}}{t} = \frac{0 - 22 m/s}{4.0 s} = -5.5 m/s^{2}$

El signo negativo se debe a que el auto está desacelerando.

Entonces, la aceleración del automovil antes de deternerse es -5.5 m/s².

Espero que te sea de utilidad!

3 0

3 years ago

From a stand on top of a bookshelf, you launch a marble with a speed of 3 m/s at a 25 degree angle with the intent of having it

Dvinal [7]

Answer:

The distance from the base of the bookcase the bucket should be placed is approximately 2.444 meters

Explanation:

The given parameters are;

The speed with which the marble was launch, u = 3 m/s

The direction in which the marble was launched = 25 degrees

The height of the launcher above the ground, h = 1.3 m

The time it takes the marble to reach maximum height, $t_{max}$ , is given as follows;

v × sinθ = g × $t_{max}$

$t_{max}$ = v × sinθ/(g) = 3×sin(25)/9.81 ≈ 0.192 seconds

The time back to the top of the bookshelf level = The time to maximum height ≈ 0.192 seconds

The time it takes the marble to reach the from top of the bookshelf level is given by the equation for free fall using the vertical component of the velocity as follows;

h = 1/2×g×t²

1.3 = 1/2 × 9.81 × t²

t² = 1.3/(1/2 × 9.81) ≈ 0.265 s²

t ≈ 0.515 seconds

Total time of flight of the marble = 0.192 seconds + 0.192 seconds + 0.515 seconds ≈ 0.899 seconds

The distance from the base of the bookcase the bucket should be placed = The total horizontal range of the marble

The total horizontal range of the marble = The horizontal component of the velocity × Time of flight of the marble

∴ The total horizontal range of the marble = u × cos(θ) × $t_{(Time \ of \ flight)}$ = 3 × cos(25) × 0.899 ≈ 2.444 meters