To solve this problem we will apply the concepts related to the kinematic equations of linear motion. Where speed is described as the distance traveled in a given time, and the successive equivalences that can be made under that equation.
The distance traveled by the girl with in the given time is
![d_g = v_g t](https://tex.z-dn.net/?f=d_g%20%3D%20v_g%20t)
The distance covered by the boy with in the given time is
![d_b = v_b t](https://tex.z-dn.net/?f=d_b%20%3D%20v_b%20t)
Since the boy will travels with twice the speed of the girl
![d_b = v_b t](https://tex.z-dn.net/?f=d_b%20%3D%20v_b%20t)
![d_b = 2v_g t](https://tex.z-dn.net/?f=d_b%20%3D%202v_g%20t)
![d_b = 2d_g](https://tex.z-dn.net/?f=d_b%20%3D%202d_g)
Half way between the two rafts at the beginnings is
![\frac{14m}{2} = 7m](https://tex.z-dn.net/?f=%5Cfrac%7B14m%7D%7B2%7D%20%3D%207m)
![7m = 2d_g](https://tex.z-dn.net/?f=7m%20%3D%202d_g)
![d_g = 3.5m](https://tex.z-dn.net/?f=d_g%20%3D%203.5m)
The final distance between the two rafts at the instant the boy reached the central point of the line joining between them is
![\Delta d = d_b-d_g](https://tex.z-dn.net/?f=%5CDelta%20d%20%3D%20d_b-d_g)
![\Delta d = 7m-3.5m](https://tex.z-dn.net/?f=%5CDelta%20d%20%3D%207m-3.5m)
![\Delta d = 10.5m](https://tex.z-dn.net/?f=%5CDelta%20d%20%3D%2010.5m)
Therefore the distance that there is between the two rafts when the first one reaches the toy is 10.5m
Answer:
Sodium sulfate(Na2SO4) is a salt
Explanation:
It is a neutralization reaction in which sulphuric acid (H2SO4) which is composed of sulfur, oxygen, and hydrogen. Sulphuric acid is strong acid reacts with 2 moles of Sodium hydroxide (in neutralization reaction 1 mole of sulphuric acid is equal to 2 moles of Sodium hydroxide) gives us 2 moles of water and sodium sulfate (Na2SO4) which is composed of sodium, sulfur, and oxygen.
Sodium sulfate (Na2SO4) is salt, when H2SO4 reacts with sodium hydroxide (due to hydrate) it will give us salt (Na2SO4)
Answer:
A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.10s later.
Explanation:
A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.0 s later. What was the rocket’s acceleration?