Answer:
An autotroph absorbs sunlight from their stoma and converts this solar energy to chemical energy with their chloroplasts. As you can see, the sun's interaction of matter and energy is vital to sustaining all living things on Earth.
Explanation:
The number of mole of HCl needed for the solution is 1.035×10¯³ mole
<h3>How to determine the pKa</h3>
We'll begin by calculating the pKa of the solution. This can be obtained as follow:
- Equilibrium constant (Ka) = 2.3×10¯⁵
- pKa =?
pKa = –Log Ka
pKa = –Log 2.3×10¯⁵
pKa = 4.64
<h3>How to determine the molarity of HCl </h3>
- pKa = 4.64
- pH = 6.5
- Molarity of salt [NaZ] = 0.5 M
- Molarity of HCl [HCl] =?
pH = pKa + Log[salt]/[acid]
6.5 = 4.64 + Log[0.5]/[HCl]
Collect like terms
6.5 – 4.64 = Log[0.5]/[HCl]
1.86 = Log[0.5]/[HCl]
Take the anti-log
0.5 / [HCl] = anti-log 1.86
0.5 / [HCl] = 72.44
Cross multiply
0.5 = [HCl] × 72.44
Divide both side by 72.44
[HCl] = 0.5 / 72.4
[HCl] = 0.0069 M
<h3>How to determine the mole of HCl </h3>
- Molarity of HCl = 0.0069 M
- Volume = 150 mL = 150 / 1000 = 0.15 L
Mole = Molarity x Volume
Mole of HCl = 0.0069 × 0.15
Mole of HCl = 1.035×10¯³ mole
<h3>Complete question</h3>
How many moles of HCl need to be added to 150.0 mL of 0.50 M NaZ to have a solution with a pH of 6.50? (Ka of HZ is 2.3 x 10 -5 .) Assume negligible volume of the HCl
Learn more about pH of buffer:
brainly.com/question/21881762
Biologists study biotic factors, and all other living things.
Answer:
2 electrons
Explanation:
Barium is present in group two. It is alkaline earth metal.
It has two valance electrons. In order to achieve noble gas configuration it loses its two valance and get complete octet.
Electronic configuration:
Ba₅₆ = [Xe] 6s²
When it loses two electron it get configuration of xenon.
Chemical properties of barium:
It form salt with halogens.e.g
Ba + Br₂ → BaBr₂
IT react with oxygen and form oxide.
2Ba + O₂ → 2BaO
this oxide form hydroxide when react with water,
BaO + H₂O → Ba(OH)₂
With nitrogen it produced nitride,
3Ba + N₂ → Ba₃N₂
With acid like HCl,
Ba + 2HCl → BaCl₂ + H₂
