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2 years ago

A college student drives 40 miles roundtrip each weekday to attend class. His car gets 18 miles per

1 answer:

3 0

In four weeks of commuting to school, it is expected the student saves a total of $13.32 if the prices went down from $2.49/gallon to $2.19.

<h3>How many gallons of gasoline does the student need each day and each week?</h3>

It is known, the total distance each day is 40 miles; moreover, the car requires 1 gallon of gasoline per 18 miles. Based on this, let's calculate the number of gallons of gasoline required:

40 miles / 18 miles = 2.22 gallons of gasoline

Now, if the student requires 2.22 gallons of gasoline everyday, the total number of gallons of gasoline per week is:

2.22 x 5 days = 11.1 gallons of gasoline
11.1 x 4= 44.4 gallons per month

<h3>How much will the student save?</h3>

Money spent with the regular gasoline price

44.4 gallons of gasoline x $2.49 = $110.55

Money spend with the new price:

44.4 gallons of gasoline x $2.19 = $97.23
$110.55-$97.23 =$13.32

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Calculate the [H3O+] of solutions a and b; calculate the [OH-] solutions c and d.

patriot [66]

Answer:

I got the answers but it won't let me post it correctly on here....

Explanation:

9.) 10-2.76 =0.0174 [H30+]= 1.74*10-3 M

10.)10-3.65=0.00224  [H3O+] =2.24*10-2 M

11.)10-3.65=0.00224 [OH-]= 2.224*10-4M

12.)10-6.87=0.00000135  [OH-]= 1.35*10-7M

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3 years ago

How many atoms in 7.55 mole of Iron atom

vagabundo [1.1K]

7.55 x 6.02 x 10²³ = 4.55 x 10²⁴ atoms

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2 years ago

AN atoms nucleus contains it's protons and electrons true or false

lesantik [10]

True, an atoms nucleus has both protons and electrons.

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3 years ago

Are elements considered to be substances?

Schach [20]

Answer:

C. Yes, because they have a definite composition.

Explanation:

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>

7 0

3 years ago

Crime scene investigators keep a wide variety of compounds on hand to help with identifying unknown substances they find in the

almond37 [142]

The powder could be acetaminophen, analgesic having chemical formula $C_{17}H_{21}NO_{4}$

<h3>What is an empirical formula?</h3>

A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule.

We are given:

Percentage of C = 67.31 %

Percentage of H = 6.978 %

Percentage of N = 4.617 %

Percentage of O = 21.10 %

Let the mass of the compound be 100 g. So, the percentages given are taken as mass.

Mass of C = 67.31 g

Mass of H = 6.978 g

Mass of N = 4.617 g

Mass of O = 21.10 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of carbon = $\frac{mass}{molar \;mass}$

Moles of carbon = $\frac{67.31g}{12g/mole}$

=5.60 moles

Moles of hydrogen = $\frac{mass}{molar \;mass}$

Moles of hydrogen = $\frac{6.978 g}{1 g/mole}$

=6.978 moles

Moles of nitrogen = $\frac{mass}{molar \;mass}$

Moles of nitrogen = $\frac{4.617 g}{14 g/mole}$

=0.329 moles

Moles of oxygen = $\frac{mass}{molar \;mass}$

Moles of oxygen = $\frac{21.10 g}{16 g/mole}$

=1.31 moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.329 moles.

We get the ratio of C : H : N : O = 17 : 21 : 1 : 4

The empirical formula for the given compound is $C_{17}H_{21}NO_{4}$ .

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3 0

2 years ago