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ValentinkaMS [17]
2 years ago
8

A college student drives 40 miles roundtrip each weekday to attend class. His car gets 18 miles per

Chemistry
1 answer:
Gekata [30.6K]2 years ago
3 0

In four weeks of commuting to school, it is expected the student saves a total of $13.32 if the prices went down from $2.49/gallon to $2.19.

<h3>How many gallons of gasoline does the student need each day and each week?</h3>

It is known, the total distance each day is 40 miles; moreover, the car requires 1 gallon of gasoline per 18 miles. Based on this, let's calculate the number of gallons of gasoline required:

  • 40 miles / 18 miles = 2.22 gallons of gasoline

Now, if the student requires 2.22 gallons of gasoline everyday, the total number of gallons of gasoline per week is:

  • 2.22 x 5 days = 11.1 gallons of gasoline
  • 11.1 x 4= 44.4 gallons per month

<h3>How much will the student save?</h3>

Money spent with the regular gasoline price

  • 44.4 gallons of gasoline x $2.49 = $110.55

Money spend with the new price:

  • 44.4 gallons of gasoline x $2.19 = $97.23
  • $110.55-$97.23 =$13.32

Learn more about gasoline price in: brainly.com/question/13898342

#SPJ1

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How Many Moles Of HCl Need To Be Added To 150.0 ML Of 0.50 M NaZ To Have A Solution With A PH Of 6.50
Aleks04 [339]

The number of mole of HCl needed for the solution is 1.035×10¯³ mole

<h3>How to determine the pKa</h3>

We'll begin by calculating the pKa of the solution. This can be obtained as follow:

  • Equilibrium constant (Ka) = 2.3×10¯⁵
  • pKa =?

pKa = –Log Ka

pKa = –Log 2.3×10¯⁵

pKa = 4.64

<h3>How to determine the molarity of HCl </h3>
  • pKa = 4.64
  • pH = 6.5
  • Molarity of salt [NaZ] = 0.5 M
  • Molarity of HCl [HCl] =?

pH = pKa + Log[salt]/[acid]

6.5 = 4.64 + Log[0.5]/[HCl]

Collect like terms

6.5 – 4.64 = Log[0.5]/[HCl]

1.86 = Log[0.5]/[HCl]

Take the anti-log

0.5 / [HCl] = anti-log 1.86

0.5 / [HCl] = 72.44

Cross multiply

0.5 = [HCl] × 72.44

Divide both side by 72.44

[HCl] = 0.5 / 72.4

[HCl] = 0.0069 M

<h3>How to determine the mole of HCl </h3>
  • Molarity of HCl = 0.0069 M
  • Volume = 150 mL = 150 / 1000 = 0.15 L
  • Mole of HCl =?

Mole = Molarity x Volume

Mole of HCl = 0.0069 × 0.15

Mole of HCl = 1.035×10¯³ mole

<h3>Complete question</h3>

How many moles of HCl need to be added to 150.0 mL of 0.50 M NaZ to have a solution with a pH of 6.50? (Ka of HZ is 2.3 x 10 -5 .) Assume negligible volume of the HCl

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brainly.com/question/21881762

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How many elements does barium have to give up to achieve a noble-gas electron configuration?
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Answer:

2 electrons

Explanation:

Barium is present in group two. It is alkaline earth metal.

It has two valance electrons. In order to achieve noble gas configuration it loses its two valance and get complete octet.

Electronic configuration:

Ba₅₆ = [Xe] 6s²

When it loses two electron it get configuration of xenon.

Chemical properties of barium:

It form salt with halogens.e.g

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IT react with oxygen and form oxide.

2Ba   +   O₂   →    2BaO

this oxide form hydroxide when react with water,

BaO  + H₂O   →  Ba(OH)₂

With nitrogen it produced nitride,

3Ba + N₂     →  Ba₃N₂

With acid like HCl,

Ba + 2HCl  →  BaCl₂ + H₂

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