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ValentinkaMS [17]
1 year ago
8

A college student drives 40 miles roundtrip each weekday to attend class. His car gets 18 miles per

Chemistry
1 answer:
Gekata [30.6K]1 year ago
3 0

In four weeks of commuting to school, it is expected the student saves a total of $13.32 if the prices went down from $2.49/gallon to $2.19.

<h3>How many gallons of gasoline does the student need each day and each week?</h3>

It is known, the total distance each day is 40 miles; moreover, the car requires 1 gallon of gasoline per 18 miles. Based on this, let's calculate the number of gallons of gasoline required:

  • 40 miles / 18 miles = 2.22 gallons of gasoline

Now, if the student requires 2.22 gallons of gasoline everyday, the total number of gallons of gasoline per week is:

  • 2.22 x 5 days = 11.1 gallons of gasoline
  • 11.1 x 4= 44.4 gallons per month

<h3>How much will the student save?</h3>

Money spent with the regular gasoline price

  • 44.4 gallons of gasoline x $2.49 = $110.55

Money spend with the new price:

  • 44.4 gallons of gasoline x $2.19 = $97.23
  • $110.55-$97.23 =$13.32

Learn more about gasoline price in: brainly.com/question/13898342

#SPJ1

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Lelu [443]

Answer:

A sodium hydroxide

Explanation:

8 0
3 years ago
Read 2 more answers
Ammonia, NH3, is used as a refrigerant. At its boiling point of –33 oC, the standard enthalpy of vaporization of ammonia is 23.3
mario62 [17]

Answer:

-68.4 kJ

Explanation:

<u>The standard enthalpy of vaporization = 23.3 kJ/mol</u>

<u>which means the energy required to vaporize 1 mole of ammonia at its boiling point (-33 °C).</u>

To calculate heat released when 50.0 g of ammonia is condensed at -33 °C.

This is the opposite of enthalpy of vaporization which means that same magnitude of heat is released.

<u>Thus,  Q = -23.3 kJ/mol</u>

<u>Where negative sign signifies release of heat</u>

Given: mass of 50.0 g

Molar mass of ammonia = 17.034 g/mol

Moles of ammonia = 50.0 /17.034 moles = 2.9353 moles

Also,

1 mole of ammonia when condenses at -33 °C releases 23.3 kJ

2.9412 moles of ammonia when condenses at -33 °C releases 23.3×2.9353 kJ

<u>Thus, amount of heat released when 50 g of ammonia condensed at -33 °C= -68.4 kJ, where negative sign signifies release of heat.</u>

4 0
3 years ago
1. What is the scientific methed?
Marrrta [24]

Answer:

The basic steps of the scientific method are:

1) make an observation that describes a problem,

2) create a hypothesis,

3) test the hypothesis, and

4) draw conclusions and refine the hypothesis. ... Critical thinking is a key component of the scientific method. Without it, you cannot use logic to come to conclusions.

5 0
2 years ago
Consider the following reaction: NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2 How many g of CO2 would be produced from the complete r
Alenkasestr [34]
<h2>1.25 g of CO_2 would be produced from the complete reaction of 25 mL of 0.833 mol/L HC_3H_3O_2 with excess NaHCO_3 </h2>

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}    

0.833M=\frac{\text{Moles of} HC_3H_3O_2\times 1000}{25ml}\\\\\text{Moles of} HC_3H_3O_2 =\frac{0.833mol/L\times 25}{1000}=0.0208mol

NaHCO_3+HC_2H_3O_2\rightarrow NaC_2H_3O_2+H_2O+CO_2

According to stoichiometry:

1 mole of HC_2H_3O_2 will give = 1 mole of CO_2

0.0208 moles of HC_2H_3O_2 will give =\frac{1}{1}\times 0.0208=0.0208 moles of CO_2

Mass of HC_2H_3O_2=moles\times {\text {molar mass}}=0.0208\times 60g/mol=1.25g

Thus 1.25 g of CO_2 would be produced from the complete reaction of 25 mL of 0.833 mol/L HC_3H_3O_2 with excess NaHCO_3

Learn more about molarity

https://brainly.in/question/13034158

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5 0
3 years ago
Calculate the atomic mass of X. The three X isotopes have atomic mass and relative abundances of 27.9769 amu (92.2297%), 28.9765
Irina18 [472]
<h3>Answer:  Si   (choice D)</h3>

This is the element Silicon.

=========================================================

Explanation:

First convert each percentage to its decimal form.

For example, 92.2297% converts to 0.922297 after moving the decimal point two spots to the left.

After doing that, multiply those decimal values with their respective atomic mass unit (amu) values.

  • 27.9769 * 0.922297 = 25.8030109393
  • 28.9765 * 0.046832 = 1.357027448
  • 29.9738 * 0.030872 = 0.9253511536

Then we add up the results

25.8030109393 + 1.357027448 + 0.9253511536 = 28.0853895409

That rounds to about 28.085

Then look at the periodic table to see the atomic mass of Cobalt (Co), Aluminum (Al), Nickel (Ni) and Silicon (Si). The mass values listed in the periodic table are weighted averages of all the isotopes. The units for the mass are still in amu.

  • Cobalt = 58.933
  • Aluminum = 26.982
  • Nickel = 58.693
  • Silicon = 28.085

We have a match with silicon, showing that <u>choice D</u> is the final answer.

7 0
1 year ago
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